Examples with solutions for Area of a Triangle: Using additional geometric shapes

Exercise #1

The trapezoid ABCD and the rectangle ABGE are shown in the figure below.

Given in cm:

AB = 5

BC = 5

GC = 3

Calculate the area of the rectangle ABGE.

555555333AAABBBCCCDDDEEEGGG

Video Solution

Step-by-Step Solution

Let's calculate side BG using the Pythagorean theorem:

BG2+GC2=BC2 BG^2+GC^2=BC^2

We'll substitute the known data:

BG2+32=52 BG^2+3^2=5^2

BG2+9=25 BG^2+9=25

BG2=16 BG^2=16

BG=16=4 BG=\sqrt{16}=4

Now we can calculate the area of rectangle ABGE since we have the length and width:

5×4=20 5\times4=20

Answer

20

Exercise #2

Given the rectangle ABCD

Given BC=X and the side AB is larger by 4 cm than the side BC.

The area of the triangle ABC is 8X cm².

What is the area of the rectangle?

S=8XS=8XS=8XX+4X+4X+4XXXAAABBBCCCDDD

Video Solution

Step-by-Step Solution

Let's calculate the area of triangle ABC:

8x=(x+4)x2 8x=\frac{(x+4)x}{2}

Multiply by 2:

16x=(x+4)x 16x=(x+4)x

Divide by x:

16=x+4 16=x+4

Let's move 4 to the left side and change the sign accordingly:

164=x 16-4=x

12=x 12=x

Now let's calculate the area of the rectangle, multiply the length and width where BC equals 12 and AB equals 16:

16×12=192 16\times12=192

Answer

192

Exercise #3

The height of the house in the drawing is 12x+9 12x+9

its width x+2y x+2y

Given the ceiling height is half the height of the square section.

Express the area of the house shape in the drawing band x and and.

Video Solution

Step-by-Step Solution

Let's draw a line in the middle of the drawing that divides the house into 2

Meaning it divides the triangle and the rectangular part.

The 2 lines represent the heights in both shapes.

If we connect the height of the roof with the height of the rectangular part, we get the total height

Let's put the known data in the formula:

12hsquare+hsquare=12x+9 \frac{1}{2}h_{\text{square}}+h_{square}=12x+9

32hsquare=12x+9 \frac{3}{2}h_{\text{square}}=12x+9

We'll multiply by two thirds and get:

hsquare=2(12x+9)3=2(4x+3) h_{\text{square}}=\frac{2(12x+9)}{3}=2(4x+3)

hsquare=8x+6 h_{\text{square}}=8x+6

If the height of the triangle equals half the height of the rectangular part, we can calculate it using the following formula:

htriangle=12(8x+6)=4x+3 h_{\text{triangle}}=\frac{1}{2}(8x+6)=4x+3

Now we can calculate the area of the triangular part:

(x+2y)×(4x+3)2=4x2+3x+8xy+6y2=2x2+1.5x+4xy+3y \frac{(x+2y)\times(4x+3)}{2}=\frac{4x^2+3x+8xy+6y}{2}=2x^2+1.5x+4xy+3y

Now we can calculate the rectangular part:

(x+2y)×(8x+6)=8x2+6x+16xy+12y (x+2y)\times(8x+6)=8x^2+6x+16xy+12y

Now let's combine the triangular area with the rectangular area to express the total area of the shape:

S=2x2+1.5x+4xy+3y+8x2+6x+16xy+12y S=2x^2+1.5x+4xy+3y+8x^2+6x+16xy+12y

S=10x2+20xy+7.5x+15y S=10x^2+20xy+7.5x+15y

Answer

3x2+8xy+112x+4y2+3y 3x^2+8xy+1\frac{1}{2}x+4y^2+3y

Exercise #4

The parallelogram ABCD and the triangle BCE are shown below.

CE = 7
DE = 15

The area of the triangle BCE is equal to 14 cm².

Calculate the area of the parallelogram ABCD.

S=14S=14S=14777BBBCCCEEEAAADDD15

Video Solution

Answer

32 cm²

Exercise #5

ABCD is a parallelogram.

AD is the diameter of a circle that has a circumference of 7π 7\pi cm.

Express the area of triangle EBC in terms of X.

X+2X+2X+2EEECCCBBBDDDAAA

Video Solution

Answer

3.5X+7cm2 3.5X + 7 cm²

Exercise #6

ACDE is a parallelogram.

DE = 12

A semicircle is placed on side FB.

If the area of the semicircle is 9π 9\pi , then what is the area of triangle ABC?

AAABBBCCCFFFEEEDDD

Video Solution

Answer

362 36\sqrt{2} cm²

Exercise #7

AD is perpendicular to BC

AD=3

The area of the triangle ABC is equal to 7 cm².

BC is the diameter of the circle on the drawing

What is the area of the circle?
Replace π=3.14 \pi=3.14

S=7S=7S=7333AAABBBCCCDDD

Video Solution

Answer

17.1 cm².

Exercise #8

Look at the triangle in the figure.

AD is used to form a semicircle with a radius of 2.5 cm.

Calculate the area of the triangle ABC.

999AAACCCBBBDDD12

Video Solution

Answer

514+30 5\sqrt{14}+30 cm².

Exercise #9

Given the triangle ABC and the deltoid ADEF

The height of the triangle is 4 cm

The base of the triangle is greater by 2 than the height of the triangle.

Segment FD cut to the middle

Calculate the area of the deltoid ADEF

444AAABBBCCCFFFEEEDDD

Video Solution

Answer

8 cm²

Exercise #10

Given the triangle ABC when the base BC a semi-circle is drawn

The radius of the circle is equal to 3 cm and its center is the point D

Given AE=3 ED

What is the area of the dotted shape?

333BBBDDDCCCAAAEEE

Video Solution

Answer

364.5π 36-\text{4}.5\pi cm².

Exercise #11

Given the trapezoid ABCD whose area is equal to 50 cm².

AB=7 DC=13

The area of the circle whose diameter FC is 2.25π 2.25\pi

How large is the area of the triangle AFD

S=50S=50S=50777131313AAABBBCCCDDDFFFEEE

Video Solution

Answer

25 cm²..