(7+x)(7+x)=?
\( (7+x)(7+x)=\text{?} \)
\( (x+1)^2+(x+2)^2= \)
\( (7+8)^2=\text{?} \)
\( (a+b)^2=\text{?} \)
\( (3x+4)^2=\text{?} \)
According to the shortened multiplication formula:
Since 7 and X appear twice, we raise both terms to the power:
In order to solve the exercise, we will need to know the abbreviated multiplication formula:
In this exercise, we will use the formula twice:
Now, we add:
x²+2x+1+x²+4x+4=
2x²+6x+5
Note that a common factor can be extracted from part of the digits:
\( x^2+10x=-25 \)
\( 4x^2=12x-9 \)
\( 2^2+12+3^2=\text{?} \)
Rewrite the following expression as a multiplication and as an addition:
\( (a+3b)^2 \)
Express the following exercise as a sum and as a power:
\( (7b+3z)(7b+3z)=\text{?} \)
Rewrite the following expression as a multiplication and as an addition:
Express the following exercise as a sum and as a power:
Solve for y:
\( y^2+4y+2=-2 \)
Solve for x:
\( x^2+32x=-256 \)
Solve for y:
Solve for x: