y=x2+10x
\( y=x^2+10x \)
\( y=2x^2-5x+6 \)
\( y=x^2 \)
\( y=x^2-6x+4 \)
\( y=2x^2-3x-6 \)
Here we have a quadratic equation.
A quadratic equation is always constructed like this:
Where a, b, and c are generally already known to us, and the X and Y points need to be discovered.
Firstly, it seems that in this formula we do not have the C,
Therefore, we understand it is equal to 0.
a is the coefficient of X², here it does not have a coefficient, therefore
is the number that comes before the X that is not squared.
In fact, a quadratic equation is composed as follows:
y = ax²-bx-c
That is,
a is the coefficient of x², in this case 2.
b is the coefficient of x, in this case 5.
And c is the number without a variable at the end, in this case 6.
\( y=-2x^2+3x+10 \)
\( y=3x^2+4x+5 \)
\( y=x^2+x+5 \)
\( y=-x^2+x+5 \)
\( y=4+3x^2-x \)
\( y=3x^2+4-5x \)
\( y=-4x^2-3x \)
\( y=-x^2+3x+40 \)
\( y=6x+3x^2-4 \)
\( y=-5x^2+x \)
\( y=-x-3x^2 \)
\( y=-6+x^2+6x \)
\( y=-3x-4x^2+3 \)
\( y=-5+x^2 \)
\( y=2x^2+3 \)