Examples with solutions for Square of sum: Data with powers and roots

Exercise #1

Simply the following expression:

(x+x)2 (x+\sqrt{x})^2

Video Solution

Step-by-Step Solution

To solve the problem, we undertake the following steps:

  • Identify the components a=xa = x and b=xb = \sqrt{x} in the expression (x+x)2(x + \sqrt{x})^2.
  • Apply the square of sum formula: (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2.
  • Substitute the values:
    • a2=x2a^2 = x^2
    • 2ab=2×x×x=2xx2ab = 2 \times x \times \sqrt{x} = 2x\sqrt{x}
    • b2=(x)2=xb^2 = (\sqrt{x})^2 = x
  • Simplifying gives: x2+2xx+xx^2 + 2x\sqrt{x} + x
  • Recognize that this can be factored to yield: x(x+2x+1)x(x + 2\sqrt{x} + 1)

Thus, the simplified expression is x[x+2x+1]\boxed{x[x + 2\sqrt{x} + 1]}.

Answer

x[x+2x+1] x\lbrack x+2\sqrt{x}+1\rbrack

Exercise #2

Solve the following equation:

(2x+1)2x+2+(x+2)22x+1=4.5x \frac{(2x+1)^2}{x+2}+\frac{(x+2)^2}{2x+1}=4.5x

Step-by-Step Solution

In order to solve the equation, start by removing the denominators.

To do this, we'll multiply the denominators:

(2x+1)2(2x+1)+(x+2)2(x+2)=4.5x(2x+1)(x+2) (2x+1)^2\cdot(2x+1)+(x+2)^2\cdot(x+2)=4.5x(2x+1)(x+2)

Open the parentheses on the left side, making use of the distributive property:

(4x2+4x+1)(2x+1)+(x2+4x+4)(x+2)=4.5x(2x+1)(x+2) (4x^2+4x+1)\cdot(2x+1)+(x^2+4x+4)\cdot(x+2)=4.5x(2x+1)(x+2)

Continue to open the parentheses on the right side of the equation:

(4x2+4x+1)(2x+1)+(x2+4x+4)(x+2)=4.5x(2x2+5x+2) (4x^2+4x+1)\cdot(2x+1)+(x^2+4x+4)\cdot(x+2)=4.5x(2x^2+5x+2)

Simplify further:

(4x2+4x+1)(2x+1)+(x2+4x+4)(x+2)=9x3+22.5x+9x (4x^2+4x+1)\cdot(2x+1)+(x^2+4x+4)\cdot(x+2)=9x^3+22.5x+9x

Go back and simplify the parentheses on the left side of the equation:

8x3+8x2+2x+4x2+4x+1+x3+4x2+4x+2x2+8x+8=9x3+22.5x+9x 8x^3+8x^2+2x+4x^2+4x+1+x^3+4x^2+4x+2x^2+8x+8=9x^3+22.5x+9x

Combine like terms:

9x3+18x2+18x+9=9x3+22.5x+9x 9x^3+18x^2+18x+9=9x^3+22.5x+9x

Notice that all terms can be divided by 9 as shown below:

x3+2x2+2x+1=x3+2.5x+x x^3+2x^2+2x+1=x^3+2.5x+x

Move all numbers to one side:

x3x3+2x22.5x2+2xx+9=0 x^3-x^3+2x^2-2.5x^2+2x-x+9=0

We obtain the following:

0.5x2x1=0 0.5x^2-x-1=0

In order to remove the one-half coefficient, multiply the entire equation by 2

x22x2=0 x^2-2x-2=0

Apply the square root formula, as shown below-

2±122 \frac{2±\sqrt{12}}{2}

Apply the properties of square roots in order to simplify the square root of 12:

2±232 \frac{2±2\sqrt{3}}{2} Divide both the numerator and denominator by 2 as follows:

1±3 1±\sqrt{3}

Answer

x=1±3 x=1±\sqrt{3}

Exercise #3

2x2+4xy+2y2+(x+y)2(x+y)= \frac{\sqrt{2x^2+4xy+2y^2+(x+y)^2}}{(x+y)}=

Video Solution

Answer

3 \sqrt{3}

Exercise #4

Solve for X:

x+x=x x+\sqrt{x}=-\sqrt{x}

Video Solution

Answer

0 0

Exercise #5

Solve the following equation:

x+1×x+2=x+3 \sqrt{x+1}\times\sqrt{x+2}=x+3

Video Solution

Answer

x=73 x=-\frac{7}{3}

Exercise #6

Look at the following equation:

xx+1x+1=1 \frac{\sqrt{x}-\sqrt{x+1}}{x+1}=1

This can also be written as:

x[A(x+B)x3]=0 x[A(x+B)-x^3]=0

Calculate A and B.

Video Solution

Answer

B=1 , A=4

Exercise #7

Solve the following system of equations:

{x+y=61+6xy=9 \begin{cases} \sqrt{x}+\sqrt{y}=\sqrt{\sqrt{61}+6} \\ xy=9 \end{cases}

Video Solution

Answer

x=6122.5 x=\frac{\sqrt{61}}{2}-2.5

y=612+2.5 y=\frac{\sqrt{61}}{2}+2.5

or

x=612+2.5 x=\frac{\sqrt{61}}{2}+2.5

y=6122.5 y=\frac{\sqrt{61}}{2}-2.5

Exercise #8

Look at the following equation:

x+x+1x+1=1 \frac{\sqrt{x}+\sqrt{x+1}}{x+1}=1

The same equation can be presented as follows:

x[A(x+B)x3]=0 x[A(x+B)-x^3]=0

Calculate A and B.

Video Solution

Answer

B=1 , A=4