The Commutative property: Only addition and subtraction

Solve:

$2-3+1$

We use the substitution property and add parentheses for the addition operation:

$(2+1)-3=$

Now, we solve the exercise according to the order of operations:

$2+1=3$

$3-3=0$

0

Solve:

$3-4+2+1$

We will use the substitution property to arrange the exercise a bit more comfortably, we will add parentheses to the addition operation:
$(3+2+1)-4=$
We first solve the addition, from left to right:
$3+2=5$

$5+1=6$
And finally, we subtract:

$6-4=2$

2

$4-2+2-4=$

Given that we are referring to addition and subtraction exercises, we solve the exercise from left to right:

$4-2=2$

$2+2=4$

$4-4=0$

$0$

$3-2+10-x=$

We solve the exercise from left to right:

$3-2=1$

$1+10=11$

Now we obtain:

$11-x$

$11-x$

$10-5-2-3=$

Given that the entire exercise is with subtraction, we solve the exercise from left to right:

$10-5=5$

$5-2=3$

$3-3=0$

$0$

$-5+2=$

If we draw a line that starts at negative five and ends at 5

We will go from the point negative five two steps forward (+2) we will arrive at the number negative 3.

$-3$

Solve:

$-5+4+1-3$

According to the order of operations, addition and subtraction are on the same level and, therefore, must be resolved from left to right.

However, in the exercise we can use the substitution property to make solving simpler.

-5+4+1-3

4+1-5-3

5-5-3

0-3

-3

$-3$

^{$(7+2+3)(7+6)(12-3-4)=\text{?}$}

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