Pythagorean Theorem in an Orthohedron

The orthohedron or cuboid is a rectangular prism, a three-dimensional figure, that is, it has length, width, and height (or depth). In addition, the angles between the different planes are right angles, which allows us to make use of the Pythagorean theorem to calculate the length of different sections of the orthohedron.

Reminder of the Pythagorean theorem:

The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. Basiclly:
a2+b2=c2a²+b² = c²
This principle can be extended to three-dimensional shapes like cuboids or orthohedrons.

Diagram of a rectangular prism (cuboid) illustrating its diagonal, labeled 'Diagonal del ortoedro.' The orange diagonal highlights the use of the Pythagorean theorem to calculate its length. Featured in a guide on applying the Pythagorean theorem to 3D shapes.

The Space Diagonal

The Pythagorean theorem can help find the length of the diagonals on the faces of an orthohedron, but it also extends to finding the space diagonal—the diagonal that runs through the interior of a cuboid from one corner to its opposite corner.

There are two methods to find this:

  1. Use the Pythagorean theorem twice: First, find one face diagonal, then use it to calculate the space diagonal.
  2. Use the formula:
    d=l2+w2+h2d=l^2+w^2+h^2​
    whereII, ww, and hh are the length, width, and height of the cuboid, respectively.

Suggested Topics to Practice in Advance

  1. The Pythagorean Theorem

Practice Using the Pythagorean Theorem in Cuboids

Examples with solutions for Using the Pythagorean Theorem in Cuboids

Exercise #1

Calculate the lengths of all possible diagonals on the faces of the rectangular prism below:

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Video Solution

Step-by-Step Solution

We will use the Pythagorean theorem to find diagonal AD1:

AA1+A1D1=AD1 AA_1+A_1D_1=AD_1

Let's input the known data:

52+72=D1A2 5^2+7^2=D_1A^2

D1A2=25+49=74 D_1A^2=25+49=74

Let's find the square root:

AD1=74 AD_1=\sqrt{74}

From the data we can see that:

AA1=DD1=5 AA_1=DD_1=5

Now let's look at triangle DD1C1 and calculate DC1 using the Pythagorean theorem:

D1D2+D1C12=C1D2 D_1D^2+D_1C_1^2=C_1D^2

Let's input the existing data:

52+42=C1D2 5^2+4^2=C_1D^2

C1D2=25+16=41 C_1D^2=25+16=41

Let's find the square root:

DC1=41 DC_1=\sqrt{41}

Now let's focus on triangle A1D1C1 and find diagonal A1C1:

A1D12+D1C12=A1C12 A_1D_1^2+D_1C_1^2=A_1C_1^2

Let's input the known data:

72+42=A1C12 7^2+4^2=A_1C_1^2

A1C12=49+16=65 A_1C_1^2=49+16=65

Let's find the square root:

A1C1=65 A_1C_1=\sqrt{65}

Now we have all 3 lengths of all possible diagonal corners in the box:

74,41,65 \sqrt{74},\sqrt{41},\sqrt{65}

Answer

74,41,65 \sqrt{74},\sqrt{41},\sqrt{65}

Exercise #2

Look at the orthohedron below.

D1C1=10 D^1C^1=10

AA1=12 AA^1=12

Calculate A1B A^1B .

101010121212AAABBBCCCDDDAAA111BBB111CCC111DDD111

Video Solution

Step-by-Step Solution

From the given data, we know that:

D1C1=A1B1=AB=10 D_1C_1=A_1B_1=AB=10

Let's draw a diagonal between A1 and B and focus on triangle AA1B.

We'll calculate A1B using the Pythagorean theorem:

AA12+AB2=A1B2 AA_1^2+AB^2=A_1B^2

Then we will substitute in the known values:

122+102=A1B2 12^2+10^2=A_1B^2

A1B2=144+100=244 A_1B^2=144+100=244

Finally, we calculate square root:

A1B=244 A_1B=\sqrt{244}

A1B=4×61=4×61 A_1B=\sqrt{4\times61}=\sqrt{4}\times\sqrt{61}

A1B=261 A_1B=2\sqrt{61}

Answer

261 2\sqrt{61}

Exercise #3

Shown below is the rectangular prism ABCDA1B1C1D1 ABCDA^1B^1C^1D^1 .

Calculate the diagonal of the rectangular prism.

777101010444AAABBBCCCDDDAAA111BBB111CCC111DDD111

Video Solution

Step-by-Step Solution

Let's look at face CC1D1D and use the Pythagorean theorem to find the diagonal of the face:

D1C12+CC12=D1C2 D_1C_1^2+CC_1^2=D_1C^2

Let's insert the known data:

102+42=D1C2 10^2+4^2=D_1C^2

116=D1C2 116=D_1C^2

Let's focus a bit on triangle BCD1 and use the Pythagorean theorem to find diagonal BD1:

D1C2+CB2=BD12 D_1C^2+CB^2=BD_1^2

Let's insert the known data:

116+72=BD12 116+7^2=BD_1^2

116+49=BD12 116+49=BD_1^2

165=BD12 165=BD_1^2

Let's find the root:

165=BD1 \sqrt{165}=BD_1

Answer

165 \sqrt{165}

Exercise #4

Look at the orthohedron in the figure below.

Which angle is between the diagonal BH and the face ABFE?

BBBCCCGGGFFFAAADDDHHHEEE

Video Solution

Answer

HBE HBE

Exercise #5

Look at the orthohedron in the figure and calculate the length of the dotted line.

444777

Video Solution

Answer

65 \sqrt{65}

Exercise #6

Look at the orthohedron in the figure below.

DCC1D1 DCC^1D^1 is a square.

How long is the dotted line?

121212555DDDAAABBBCCCD1D1D1A1A1A1B1B1B1C1C1C1

Video Solution

Answer

13 13

Exercise #7

ABCDA1B1C1D1 ABCDA^1B^1C^1D^1 is a rectangular prism.

AB=7 AB=7
AA1=5 AA^1=5

Calculate the diagonal of the rectangular prism.

777555AAABBBCCCDDDAAA111BBB111CCC111DDD111

Video Solution

Answer

Not enough data

Exercise #8

Calculate the length of the dotted diagonal in the rectangular prism.

3X3X3XXXX

Video Solution

Answer

x10 x\sqrt{10}

Exercise #9

Look at the box in the drawing and calculate the indicated diagonal.777888

Video Solution

Answer

113 \sqrt{113}

Exercise #10

Look at the rectangular prism in the figure and express the length of the diagonal using the sides EA,CD,FG EA,CD,FG .

AAABBBCCCDDDEEEFFFGGGHHH

Video Solution

Answer

CD2+FG2+EA2 \sqrt{CD^2+FG^2+EA^2}

Exercise #11

A cube has a side length of 5 cm.

Calculate the diagonal of the cube.

555AAABBBCCCDDDAAA111BBB111CCC111DDD111

Video Solution

Answer

53 5\sqrt{3}

Exercise #12

A cuboid has a width measuring 8 cm and a height of 4 cm.

Calculate the length of the side AC.

888444DDDBBBAAACCC

Video Solution

Answer

80 \sqrt{80} cm

Exercise #13

A rectangular prism has a height twice as long as its length.

Its width is 3 times greater than its height.

How many times greater is its diagonal than its length?

6X6X6XXXX2X2X2XAAABBBCCCDDDEEEFFFGGGHHH

Video Solution

Answer

41 \sqrt{41}

Exercise #14

Given the cuboid whose length is equal to 9 cm

Width is equal to 3 cm

Side AB equals 10 cm

Is it possible to calculate the volume of the cuboid?

999333101010AAABBB

Video Solution

Answer

You can, 3619 36\cdot\sqrt{19} cm³

Exercise #15

Look at the orthohedron below.

DC=DD1 DC=DD_1

What is the length of the orthohedron's diagonal?

888101010AAABBBCCCDDDAAA111BBB111CCC111DDD111

Video Solution

Answer

264 \sqrt{264}