Rules of Roots Combined: Solving the equation

Solve the following equation:

$\frac{\sqrt{64}}{\sqrt{4}}=2x$

2

$\frac{\sqrt{98}}{\sqrt{x}}=7$

$2$

Solve for x:

$\sqrt{6}x=\sqrt{36}$

$\sqrt{6}$

Solve the following equation:

$\frac{\sqrt{90}}{\sqrt{x}}=3$

10

Solve the following equation:

$\frac{\sqrt{50}}{\sqrt{x}}=5$

Answers b and c

Solve the following equation:

$\sqrt{2}\cdot\sqrt{3}=\frac{x}{\sqrt{6}}$

6

Solve for x:

$\frac{\sqrt{20}\cdot\sqrt{5}}{x}=2\cdot\sqrt{25}$

$1$

Solve the following exercise:

$\sqrt{\sqrt{81}}=\sqrt[3]{\sqrt{x^6}}$

$x=3$

Solve for x:

$\frac{\sqrt{8}\cdot\sqrt{4}\cdot\sqrt{2}}{\sqrt{2}}=\sqrt{x^2}$

$x=\sqrt{32}$

Solve the following equation:

$\frac{\sqrt{4}\cdot\sqrt{5}}{\sqrt{10}}=x$

$\sqrt{2}$

Solve for x:

$\frac{\sqrt{2}\cdot\sqrt{4}}{\sqrt{16}}=\frac{x}{\sqrt{8}}$

$2$

Solve the following exercise:

$\sqrt{x^6}=\sqrt{\sqrt{16}}\cdot\sqrt{25}$

$x^3=10$

Solve the following exercise:

$\sqrt{144}=\sqrt[3]{\sqrt[5]{x^{10\cdot3}}}$

$x^2=12$

Solve the following exercise:

$\sqrt[5]{\sqrt[]{x^{10}}}=\sqrt{\sqrt{81}}$

$x=3$

Solve the following exercise:

$\sqrt{\frac{16}{\sqrt[3]{64}}}=\sqrt{x^2}$

$x=2$

Solve for x:

$\frac{\sqrt{4}\cdot\sqrt{5}}{\sqrt{25}}=2x$

$x=\frac{\sqrt{20}}{10}$