Product Property of Square Roots: Using multiple rules

Introduction:

We will address the following three laws of exponents:

a. Definition of root as an exponent:

$\sqrt[n]{a}=a^{\frac{1}{n}}$

b. The law of exponents for exponents applied to multiplication of terms in parentheses:

$(a\cdot b)^n=a^n\cdot b^n$

c. The law of exponents for exponents applied to division of terms in parentheses:

$(\frac{a}{b})^n=\frac{a^n}{b^n}$

Note:

(1). By combining the two laws of exponents mentioned in a (in the first and third steps later) and b (in the second step later), we can obtain a new rule:

$\sqrt[n]{a\cdot b}=\\ (a\cdot b)^{\frac{1}{n}}=\\ a^{\frac{1}{n}}\cdot b^{\frac{1}{n}}=\\ \sqrt[n]{a}\cdot \sqrt[n]{ b}\\ \downarrow\\ \boxed{\sqrt[n]{a\cdot b}=\sqrt[n]{a}\cdot \sqrt[n]{ b}}$

And specifically for the fourth root we get:

$\boxed{ \sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{ b}}$

(2). Similarly, note that by combining the two laws of exponents mentioned in a (in the first and third steps later) and c (in the second step later), we can obtain another new rule:

$\sqrt[n]{\frac{a}{b}}=\\ (\frac{a}{b})^{\frac{1}{n}}=\\ \frac{a^{\frac{1}{n}}}{ b^{\frac{1}{n}}}=\\ \frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}\\ \downarrow\\ \boxed{ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}}$

And specifically for the fourth root we get:

$\boxed{ \sqrt{\frac{a}{ b}}=\frac{\sqrt{a}}{\sqrt{ b}} }$

Therefore, in solving the problem, meaning - in simplifying the given expression, we will use the two new rules we received in the introduction:

(1).

$\boxed{ \sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{ b}}$

(2).

$\boxed{ \sqrt{\frac{a}{ b}}=\frac{\sqrt{a}}{\sqrt{ b}} }$

We'll start by simplifying the expression in the numerator using the rule we received in the introduction (1) (but in the opposite direction, meaning we'll insert the multiplication of roots as a multiplication of terms under the same root) Then we'll perform the multiplication under the root in the numerator:

$\frac{\sqrt{20}\cdot\sqrt{4}}{\sqrt{5}}= \\ \frac{\sqrt{20\cdot4}}{\sqrt{5}}= \\ \frac{\sqrt{80}}{\sqrt{5}}= \\$We'll continue and simplify the fraction, using the rule we received in the introduction (2) (but in the opposite direction, meaning we'll insert the division of roots as a division of terms under the same root) Then we'll reduce the fraction under the root:

$\frac{\sqrt{80}}{\sqrt{5}}= \\ \\ \sqrt{\frac{80}{5}}=\\ \sqrt{16}=\\ \boxed{4}$

In the final stage, after reducing the fraction under the root, we used the known fourth root of the number 16.

Let's summarize the simplification process of the expression in the problem:

$\frac{\sqrt{20}\cdot\sqrt{4}}{\sqrt{5}}= \\ \frac{\sqrt{80}}{\sqrt{5}}= \\ \sqrt{16}=\\ \boxed{4}$

Therefore, the correct answer is answer B.

Introduction:

We will address the following three laws of exponents:

a. Definition of root as an exponent:

$\sqrt[n]{a}=a^{\frac{1}{n}}$

b. The law of exponents for exponents applied to multiplication of terms in parentheses:

$(a\cdot b)^n=a^n\cdot b^n$

c. The law of exponents for exponents applied to division of terms in parentheses:

$(\frac{a}{b})^n=\frac{a^n}{b^n}$

Note:

d. By combining the two laws of exponents mentioned in a' (in the first and third steps later) and b' (in the second step later), we can obtain a new rule:

$\sqrt[n]{a\cdot b}=\\ (a\cdot b)^{\frac{1}{n}}=\\ a^{\frac{1}{n}}\cdot b^{\frac{1}{n}}=\\ \sqrt[n]{a}\cdot \sqrt[n]{ b}\\ \downarrow\\ \boxed{\sqrt[n]{a\cdot b}=\sqrt[n]{a}\cdot \sqrt[n]{ b}}$

And specifically for the fourth root we get:

$\boxed{ \sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{ b}}$

e. Similarly, note that by combining the two laws of exponents mentioned in a' (in the first and third steps later) and c' (in the second step later), we can obtain another new rule:

$\sqrt[n]{\frac{a}{b}}=\\ (\frac{a}{b})^{\frac{1}{n}}=\\ \frac{a^{\frac{1}{n}}}{ b^{\frac{1}{n}}}=\\ \frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}\\ \downarrow\\ \boxed{ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}}$

And specifically for the fourth root we get:

$\boxed{ \sqrt{\frac{a}{ b}}=\frac{\sqrt{a}}{\sqrt{ b}} }$

Therefore, in solving the problem, that is - in simplifying the given expression, we will use the two new rules we received in the introduction:

(1).

$\boxed{ \sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{ b}}$$$(2).

$\boxed{ \sqrt{\frac{a}{ b}}=\frac{\sqrt{a}}{\sqrt{ b}} }$

We'll start by simplifying the expression in the numerator using the rule we received in the introduction (1) (but in the opposite direction, meaning we'll insert the multiplication of roots as a multiplication of terms under the same root) then we'll perform the multiplication under the root in the numerator:

$\frac{\sqrt{70}\cdot\sqrt{10}}{\sqrt{7}}= \\ \frac{\sqrt{70\cdot10}}{\sqrt{7}}= \\ \frac{\sqrt{700}}{\sqrt{7}}= \\$We'll continue and simplify the fraction, using the rule we received in the introduction (2) (but in the opposite direction, meaning we'll insert the division of roots as a division of terms under the same root) then we'll reduce the fraction under the root:

$\frac{\sqrt{700}}{\sqrt{7}}= \\ \sqrt{\frac{700}{7}}=\\ \sqrt{100}=\\ \boxed{10}$

In the final stage, after reducing the fraction under the root, we used the known fourth root of the number 100.

Let's summarize the process of simplifying the expression in the problem:

$\frac{\sqrt{70}\cdot\sqrt{10}}{\sqrt{7}}= \\ \frac{\sqrt{700}}{\sqrt{7}}= \\ \sqrt{100}=\\ \boxed{10}$

Therefore, the correct answer is answer a'.

Introduction:

We will address the following two laws of exponents:

a. The definition of root as an exponent:

$\sqrt[n]{a}=a^{\frac{1}{n}}$

b. The law of exponents for an exponent applied to terms in parentheses:

$(\frac{a}{b})^n=\frac{a^n}{b^n}$

Note:

By combining these two laws of exponents mentioned in a (in the first and third steps below) and b (in the second step below), we can derive another new rule:

$\sqrt[n]{\frac{a}{b}}=\\ (\frac{a}{b})^{\frac{1}{n}}=\\ \frac{a^{\frac{1}{n}}}{ b^{\frac{1}{n}}}=\\ \frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}\\ \downarrow\\ \boxed{ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}}$

Therefore, in solving the problem, meaning - simplifying the given expression, we will use the new rule we received in the introduction:

$\boxed{ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{ \sqrt[n]{ b}}}$

We'll start by simplifying the expression using the rule we received in the introduction (but in the opposite direction, meaning we'll insert the product of roots as a product of terms under the same root) then we'll perform the multiplication under the root and finally we'll perform the fifth root operation:

$\frac{\sqrt[4]{128}}{\sqrt[4]{8}}= \\ \sqrt[4]{\frac{128}{8}}=\\ \sqrt[4]{16}=\\ \boxed{2}$

Therefore, the correct answer is answer B.