AD = BC
AD || BC
According to which theorem are the triangles ΔADB≅ΔCBD congruent?
AD = BC
AD || BC
According to which theorem are the triangles ΔADB≅ΔCBD congruent?
We are given: AD=BC
The angle ADB is equal to the angle CBD since AD is parallel to BC and the corresponding angles are equal between parallel lines.
DB=DB since it is a common side.
Therefore, we have two triangles that are congruent according to the S.A.S. (side, angle, side) theorem.
According to the S.A.S. theorem