Triangle Area Calculation: Finding Area with 3m Base and 2/3m Height

Question

What is the area of a triangle whose side length is3 3 meters and its height 23 \frac{2}{3} meters?

Video Solution

Solution Steps

00:00 Find the area of the triangle
00:03 We'll use the formula for calculating triangle area
00:06 (base times height) divided by 2, we'll substitute lengths according to the given data
00:15 We'll convert from whole number to whole fraction
00:22 Make sure to multiply numerator by numerator and denominator by denominator
00:27 We'll reduce what's possible
00:37 We'll convert from whole fraction to whole number
00:41 And this is the solution to the question

Step-by-Step Solution

To determine the area of the triangle, we will proceed as follows:

  • Identify the base and height from the problem.
  • Use the formula for the area of a triangle, A=12×b×h A = \frac{1}{2} \times b \times h .
  • Substitute the given values and compute the area.

First, the base b b of the triangle is 3 3 meters, and the height h h is 23 \frac{2}{3} meters. To find the area, we will use the formula:

A=12×b×h A = \frac{1}{2} \times b \times h

Substituting, we get:

A=12×3×23 A = \frac{1}{2} \times 3 \times \frac{2}{3}

We begin by calculating the multiplication inside the formula:

A=12×(3×23) A = \frac{1}{2} \times \left(3 \times \frac{2}{3}\right)

Here, 3×23=63=2 3 \times \frac{2}{3} = \frac{6}{3} = 2 .

Then, multiply by 12 \frac{1}{2} :

A=12×2=1 A = \frac{1}{2} \times 2 = 1 .

The area of the triangle is 1 1 square meter.

The correct answer from the choices provided is: 1 1 .

Answer

1 1