Calculate Area: 5½ Meters × ⅔ Meter Rectangle Problem

Question

What is the area of a pool that has a length of 512 5\frac{1}{2} meters and a width of 23 \frac{2}{3} of a meter?

Video Solution

Step-by-Step Solution

To solve this problem, we need to find the area of a pool with a given length and width.

  • Step 1: Convert the mixed number to an improper fraction.
  • Step 2: Multiply the two fractions to find the area.
  • Step 3: Simplify the result if necessary.

First, let's convert the length from a mixed number to an improper fraction. The length is 512 5\frac{1}{2} meters, which can be written as an improper fraction:

512=112 5\frac{1}{2} = \frac{11}{2}

The width is already given as a fraction: 23 \frac{2}{3} meters.

Step 2: To find the area of the pool, we multiply the length by the width:

Area=(112)×(23) \text{Area} = \left(\frac{11}{2}\right) \times \left(\frac{2}{3}\right)

Now, multiply the numerators together and the denominators together:

Area=11×22×3=226 \text{Area} = \frac{11 \times 2}{2 \times 3} = \frac{22}{6}

Step 3: Let's simplify 226 \frac{22}{6} . The greatest common divisor of 22 and 6 is 2, so dividing the numerator and the denominator by 2 gives:

22÷26÷2=113 \frac{22 \div 2}{6 \div 2} = \frac{11}{3}

This can be further expressed as a mixed number:

113=323 \frac{11}{3} = 3\frac{2}{3}

Therefore, the area of the pool is 323 3\frac{2}{3} square meters.

Answer

323 3\frac{2}{3}