Subtract 8 from 72: Vertical Format Arithmetic Problem

Question

amp;72amp;amp;  8amp;776amp; \begin{aligned} &72 \\ -& \\ &~~8 \\ &\underline{\phantom{776}} & \\ \end{aligned}

Video Solution

Solution Steps

00:00 Solve
00:03 Each time consider a shortage of 2 digits, and then place
00:06 2 is less than 8
00:09 Therefore, subtract 1 from the tens and add this amount to the ones
00:15 In other words, now instead of 2 we'll have 12
00:18 Subtract the ones from the ones plus the ten
00:25 Place in ones
00:28 Place 0 in the missing digits
00:31 Subtract tens from tens, and place in tens
00:35 And this is the solution to the question

Step-by-Step Solution

To solve this vertical subtraction problem, follow these steps:

Step 1: Set up the problem vertically.

Write 72 and 8 ensuring that the digits are aligned according to their place values:

72
- 8
72\underline{\phantom{72}}

Step 2: Start subtracting from the rightmost digit (ones place).

In the ones place, we have 2 (from 72) and 8 (from -8). Since 2 is less than 8, we need to regroup.

Step 3: Perform regrouping.

Take 1 ten from the tens place of 72, leaving 6 tens. Adding 10 ones to 2 makes it 12 in the ones place.

Rewritten, the problem now looks like this:

6 12
- 8
72\underline{\phantom{72}}

Step 4: Continue with subtraction in the ones place.

Subtract 8 from 12, which equals 4.

Step 5: Subtract in the tens place.

Now, move to the tens place. We have 6 tens (from the regrouped value) and since there is no tens digit to subtract, it remains 6.

Conclusion: Combine the results from each place value to find the final difference: 66 tens and 44 ones make 6464.

Therefore, the solution to the problem is 64 64 .

Answer

64