Subtract 15 from 33: Vertical Format Arithmetic Problem

Video Solution

Solution Steps

00:00 Solve

00:03 Each time we consider it as a subtraction of 2 digits, and then we place

00:06 3 is less than 5

00:09 So we subtract 1 from the tens and add this amount to the units

00:16 Which means now instead of 3 we will have 13

00:23 We subtract the units from the units plus ten

00:26 Place in units

00:31 Subtract tens from tens, and place in tens

00:35 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

Write the numbers 33 and 15 vertically, aligning by the rightmost digits.
Subtract the digit in the units place, which is 3 (from 33) minus 5 (from 15). Since 3 is less than 5, we need to borrow 1 ten from the tens place.
After borrowing, the units digit becomes 13 (instead of 3).
Now, perform the subtraction: 13 - 5 equals 8.
Proceed to the tens place: We borrowed 1, leaving 2 in the tens column of 33.
Subtract the tens: 2 - 1 equals 1.

The final answer, after borrowing and executing the subtraction, is $(33 - 15)$ which equals $18$ .

Therefore, the solution to the problem is $18$ .