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We will solve the problem using vertical addition as follows:
First, add the digits in the units place:
.
Since 10 is composed of 0 in the units place and carry over 1 to the tens place, write 0 in the units place and remember to carry over the 1.
Next, move to the tens place and add up the digits, considering the carryover:
.
Finally, add the hundreds place, which has no other digits to add:
Summarizing, the addition yields the following:
Therefore, the result of adding 957 and 3 is .
The correct answer from the choices given is Choice 4: 960.
Thus, the correct solution to the problem is .
960
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When adding digits gives you 10 or more, you write the ones digit in that column and carry the tens digit to the next column. For example, 7 + 3 = 10, so write 0 and carry 1.
We start from the units place (rightmost) because any carrying affects the next column to the left. This ensures we handle all place values correctly.
Treat missing digits as zero. In this problem, the tens place of 3 is really 0, so we add 5 + 0 + 1 (carry) = 6.
Check that each column sum makes sense: units: 7+3=10 (write 0, carry 1), tens: 5+0+1=6, hundreds: 9+0=9. Final answer: 960!
It's much harder! You might need to adjust previous columns when carrying happens. Always work right to left for vertical addition.
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