Solve the Square Root Product: √4 × √4 Step-by-Step

Question

Solve the following exercise:

44= \sqrt{4}\cdot\sqrt{4}=

Video Solution

Solution Steps

00:00 Solve
00:03 Root of number (A) times root of another number (B)
00:07 Equals the root of their product (A times B)
00:11 Let's use this formula in our exercise and calculate the product
00:14 Let's calculate the root of 16
00:17 And this is the solution to the question

Step-by-Step Solution

In order to simplify the given expression, we will use two laws of exponents:

a. The definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}} b. The law of exponents for power of a power:

(am)n=amn (a^m)^n=a^{m\cdot n}

Let's start by converting the square roots to exponents using the law mentioned in a':

44=412412= \sqrt{4}\cdot\sqrt{4}= \\ \downarrow\\ 4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}= Let's continue, notice that we got a number multiplied by itself, therefore, according to the definition of exponents we can write the expression we got as a power of that same number, then - we'll use the law of exponents mentioned in b' and perform the exponent operation on the term in parentheses:

412412=(412)2=4122=41=4 4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}= \\ (4^{\frac{1}{2}})^2=\\ 4^{\frac{1}{2}\cdot2}=\\ 4^1=\\ \boxed{4} Therefore, the correct answer is answer c.

Answer

4 4