Solve the Square Root Equation: x^6 = √16 · √25

Question

Solve the following exercise:

x6=1625 \sqrt{x^6}=\sqrt{\sqrt{16}}\cdot\sqrt{25}

Video Solution

Solution Steps

00:00 Solve the following problem
00:04 A "Regular root" is of the order 2
00:10 Breakdown 16 to 4 squared
00:13 Breakdown 25 to 5 squared
00:16 When we have a root of the order (C) on number (A) to the power of (B)
00:19 The result equals the number (A) to the power of (B divided by C)
00:22 We'll apply this formula to our exercise
00:28 The root cancels the square
00:34 Calculate the power quotient
00:40 Breakdown 4 to 2 squared
00:43 The root cancels the square
00:47 This is the solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify 16 \sqrt{\sqrt{16}} .
  • Step 2: Simplify 25 \sqrt{25} .
  • Step 3: Calculate the right-hand side.
  • Step 4: Solve x6= \sqrt{x^6} = computed right-hand side.

Now, let's work through each step:
Step 1: Simplify 16 \sqrt{\sqrt{16}} .
We know that 16=4 \sqrt{16} = 4 , and 4=2 \sqrt{4} = 2 . So, 16=2 \sqrt{\sqrt{16}} = 2 .

Step 2: Simplify 25 \sqrt{25} .
We know that 25=5 \sqrt{25} = 5 .

Step 3: Calculate the entire right-hand side.
We have 1625=25=10 \sqrt{\sqrt{16}} \cdot \sqrt{25} = 2 \cdot 5 = 10 .

Step 4: Solve x6=10 \sqrt{x^6} = 10 .
Rewrite the left side as (x6)1/2=x6/2=x3 (x^6)^{1/2} = x^{6/2} = x^3 .
Thus, x3=10 x^3 = 10 .

Therefore, the solution to the problem is x3=10 x^3 = 10 .

Answer

x3=10 x^3=10