Solve the Polynomial Equation: 12x⁴ - 3x³ = 0

Question

12x43x3=0 12x^4-3x^3=0

Video Solution

Solution Steps

00:00 Find X
00:03 Factor with the term 3X cubed
00:13 Take out the common factor from the parentheses
00:29 This is one solution that makes the equation zero
00:39 Now let's check which solutions zero out the second factor
00:43 Isolate X
00:47 And this is the solution to the question

Step-by-Step Solution

To solve this polynomial equation, we'll follow these steps:

  • Step 1: Identify and factor out the greatest common factor (GCF).
  • Step 2: Solve the resulting simpler equations for xx.
  • Step 3: Verify the solutions.

Now, let's work through each step:

Step 1: Factor out the Greatest Common Factor (GCF)

The given equation is 12x43x3=0 12x^4 - 3x^3 = 0 .
Both terms share a common factor of 3x3 3x^3 . Factoring out this common factor, we get:

3x3(4x1)=0 3x^3(4x - 1) = 0

Step 2: Solve the factored equation

We now have two factors: 3x3 3x^3 and (4x1) (4x - 1) . Set each factor to zero to find possible solutions:

  • For the factor 3x3=0 3x^3 = 0 :
    Solving this gives x3=0 x^3 = 0 , which implies x=0 x = 0 .
  • For the factor 4x1=0 4x - 1 = 0 :
    Solving this gives 4x=1 4x = 1 , leading to x=14 x = \frac{1}{4} .

Step 3: Verification

Substitute x=0 x = 0 and x=14 x = \frac{1}{4} back into the original equation to verify:

  • Substituting x=0 x = 0 :
    12(0)43(0)3=0 12(0)^4 - 3(0)^3 = 0 , which is true.
  • Substituting x=14 x = \frac{1}{4} :
    Calculations show 12(14)43(14)3=0 12\left(\frac{1}{4}\right)^4 - 3\left(\frac{1}{4}\right)^3 = 0 , which also holds true.
Therefore, the solutions to the problem are x=0 x = 0 and x=14 x = \frac{1}{4} .

The correct choice from the given options is x=0,14 x = 0, \frac{1}{4} .

Therefore, the solution to the problem is x=0,14 x=0,\frac{1}{4} .

Answer

x=0,14 x=0,\frac{1}{4}