Solve the Fraction Subtraction: 3/4 - 1/6 Step by Step

Solve the following exercise:

3416=? \frac{3}{4}-\frac{1}{6}=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:05 Let's solve this problem together.
00:08 First, we need to find the least common denominator.
00:12 We'll multiply by three, and then by two, to find it.
00:17 Remember to multiply both the top and bottom numbers.
00:21 Now, let's do those multiplications. Great job!
00:29 Next, we subtract using the common denominator.
00:35 Let's calculate the top number, or the numerator.
00:40 And there you have it. That's the solution!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following exercise:

3416=? \frac{3}{4}-\frac{1}{6}=\text{?}

2

Step-by-step solution

To solve the problem of subtracting the fractions 34 \frac{3}{4} and 16 \frac{1}{6} , we follow these steps:

  • First, identify the least common denominator (LCD) of the given fractions' denominators. The numbers 4 and 6 have an LCD of 12.
  • Next, convert each fraction to have this common denominator.

The fraction 34 \frac{3}{4} is converted by determining what number we multiply 4 by to get 12 (which is 3). Thus, multiply both the numerator and the denominator by 3:
34=3×34×3=912 \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} .

The fraction 16 \frac{1}{6} is converted by determining what number we multiply 6 by to get 12 (which is 2). Hence, multiply both the numerator and the denominator by 2:
16=1×26×2=212 \frac{1}{6} = \frac{1 \times 2}{6 \times 2} = \frac{2}{12} .

  • Now that both fractions have the common denominator, subtract the numerators:

912212=9212=712 \frac{9}{12} - \frac{2}{12} = \frac{9 - 2}{12} = \frac{7}{12} .

The solution is the fraction 712 \frac{7}{12} .

In conclusion, the answer to this problem is 712 \frac{7}{12} .

3

Final Answer

712 \frac{7}{12}

Practice Quiz

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Solve the following exercise:

\( \frac{3}{2}-\frac{1}{2}=\text{?} \)

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