13⋅2x:(4a⋅z5)=?
Firstly, let's rewrite the exercise as a fraction:
4a13×2x:z5=
Next, we'll factor out the 4 from the denominator of the first fraction into a smaller multiplication exercise and invert the second fraction to create a multiplication exercise:
2×2×a13×2x×5z=
We'll now reduce the 2 in the numerator and denominator of the first fraction:
2×a13×x×5z=
We'll then multiply the two multiplication exercises:
2×a×513×x×z=10a13xz
Finally, we divide 13 by 10 to get:
1.3axz
1.3axz