Solve the Equation: x⁴ + 2x² = 0 Using Factor Method

x4+2x2=0 x^4+2x^2=0

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:04 Factor with the X² term
00:15 Take out the common factor from the parentheses
00:18 This is one solution that zeros the equation
00:26 Now let's check which solutions zero the second factor
00:30 Isolate X
00:34 Any number squared is necessarily positive, therefore there is no solution
00:38 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

x4+2x2=0 x^4+2x^2=0

2

Step-by-step solution

To solve the equation x4+2x2=0x^4 + 2x^2 = 0, we will use the technique of factoring. Let's proceed step-by-step:

First, notice that both terms x4x^4 and 2x22x^2 have a common factor of x2x^2. We can factor x2x^2 out from the equation:

x2(x2+2)=0x^2(x^2 + 2) = 0

Now, to solve for xx, we apply the Zero Product Property, which gives us that at least one of the factors must be zero:

  • x2=0x^2 = 0 or
  • x2+2=0x^2 + 2 = 0

Solving the first case, x2=0x^2 = 0:

x=0x = 0

For the second case, x2+2=0x^2 + 2 = 0, we reach:

x2=2x^2 = -2

Since x2=2x^2 = -2 has no real solutions (squares of real numbers are non-negative), we can conclude that this equation doesn't provide additional real solutions.

Therefore, the only real solution to the given equation is x=0x = 0.

The correct choice from the provided options is:

x=0 x=0

3

Final Answer

x=0 x=0

Practice Quiz

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Solve the following equation:


\( 2x^2-8=x^2+4 \)

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