Solve the Equation: 32(? + ?) = 8 + 2a - Finding Missing Values

To solve the equation $32(?+?)=8+2a$, follow these steps:

• First, observe the equation: $32(? + ?) = 8 + 2a$.
• Factor out $32$ on the left side: it should already involve distribution.
• On the right side, we see $8 + 2a$ can potentially be related to $32$: $8 = \frac{1}{4} \cdot 32$ and $2a = \frac{1}{16}a \cdot 32$.
• Therefore, express the equation as:

$32\left(\frac{1}{4} + \frac{1}{16}a\right) = 8 + 2a$

This demonstrates that the missing values to satisfy the equation's balance, by distribution properties, are:

$\frac{1}{4} \text{ and } \frac{1}{16}a$

Thus, the completed form of the right side of the equation with respect to $32$ is:

Hence, the solution is: $\frac{1}{4}, \frac{1}{16}a$.