Solve Mixed Number Multiplication: 3⅓ × 2⅕ Step-by-Step

Question

3515×2210= 3\frac{5}{15}\times2\frac{2}{10}=

Video Solution

Step-by-Step Solution

To solve this problem, follow these steps:

  • Step 1: Convert mixed numbers to improper fractions.
  • Step 2: Simplify the fractions if feasible.
  • Step 3: Multiply the improper fractions.
  • Step 4: Convert the result back to a mixed number.

Let's work through the steps:

Step 1: Convert the mixed numbers to improper fractions.

3515=3+515=4515+515=50153\frac{5}{15} = 3 + \frac{5}{15} = \frac{45}{15} + \frac{5}{15} = \frac{50}{15}, simplifying yields 103\frac{10}{3}.

2210=2+210=2010+210=22102\frac{2}{10} = 2 + \frac{2}{10} = \frac{20}{10} + \frac{2}{10} = \frac{22}{10}, simplifying yields 115\frac{11}{5}.

Step 2: Multiply the fractions.

103×115=11015\frac{10}{3} \times \frac{11}{5} = \frac{110}{15}.

Step 3: Simplify the result of the multiplication.

11015\frac{110}{15} can be simplified by dividing the numerator and the denominator by 5, yielding 223\frac{22}{3}.

Step 4: Convert the resulting improper fraction back to a mixed number.

Dividing, 22÷3=722 \div 3 = 7 with a remainder of 1, so 223=713\frac{22}{3} = 7\frac{1}{3}.

Therefore, the solution to the problem is 7137\frac{1}{3}.

Answer

713 7\frac{1}{3}