Solve the following problem:
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Solve the following problem:
Recall the order of operations: parentheses precede all other operations, multiplication and division follow (from left to right) and finally addition and subtraction (from left to right)
When there are parentheses within parentheses, we start with the innermost ones first.
In this exercise, there are only multiplication and division operations and parentheses within parentheses.
Therefore, we will first perform the operation in the innermost parentheses, and after calculating we can remove the inner parentheses. We'll continue doing this until there are no more parentheses in the exercise.
Now we'll perform the operation in the remaining parentheses and after calculating we'll remove the parentheses entirely:
Once again we'll perform the operation in the remaining parentheses and after calculating we'll remove the parentheses entirely
Shown below is the solution that we obtained expressed as a fraction. Proceed to reduce it.
The largest number by which we can reduce the fraction is 3:
Proceed to solve it:
Therefore the answer is option c -
\( 100-(5+55)= \)
The order of operations requires you to handle parentheses first. When there are nested parentheses, you must work from the inside out, just like peeling an onion layer by layer!
The colon (:) means division, just like the ÷ symbol. So is the same as .
Keep reducing until the numerator and denominator have no common factors other than 1. For , both are divisible by 3, giving which cannot be reduced further.
While you might be able to do some steps mentally, it's much safer to write out each step when dealing with nested parentheses. One small mistake can throw off your entire answer!
Use the acronym PEMDAS (Parentheses, Exponents, Multiplication/Division, Addition/Subtraction). Always handle the deepest parentheses first, then work outward step by step.
That's normal! When you divide a small number (3) by a larger number (12), you get a fraction less than 1. Division can make numbers smaller, especially when the dividend is less than the divisor.
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