Solve 2×(200÷(35×3)): Order of Operations Challenge

Solve the following problem:

2×(200:(35×3))= 2\times(200:(35\times3))=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Let's write division as a fraction
00:13 Let's write everything in the same fraction
00:17 Let's break down 200 into factors 40 and 5
00:28 Let's break down 35 into factors 5 and 7
00:36 Let's reduce what we can
00:51 Let's break down 80 into 63 plus 17
00:58 Let's split the fraction into 2 fractions
01:09 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the following problem:

2×(200:(35×3))= 2\times(200:(35\times3))=

2

Step-by-step solution

Recall the order of operations: parentheses precede all other operations, proceed to perform multiplication and division (from left to right) finally address the addition and subtraction operations (from left to right)

When there are parentheses within parentheses, start with the innermost ones first.

2×(200:(35×3))= 2\operatorname{\times}(200:(35\operatorname{\times}3))=

In this exercise, there are only multiplication and division operations and parentheses within parentheses.

Therefore, we will first perform the operation in the inner parentheses, after which we can remove the inner parentheses. We'll continue doing this until no more parentheses remain in the exercise.

2×(200:(35×3))=2×(200:(105))= 2\times(200:(35\times3))=2\times(200:(105))=

2×(200:(105))=2×(200:105)= 2\times(200:(105))= 2\times(200:105) =

Express the value obtained from the inner parentheses as a fraction and proceed to reduce it.

Reminder - How do we approach reducing a fraction? Divide both the numerator and denominator by the same number

2×(200:105)=2×(200105)= 2\times(200:105)=2\times(\frac{200}{105})=
The largest number by which we can reduce the fraction is 5

2×(200105)=2×(200:5105:5)= 2\times(\frac{200}{105})= 2\times(\frac{200:5}{105:5})=

2×(200:5105:5)=2×(4021)= 2\times(\frac{200:5}{105:5})= 2\times(\frac{40}{21})=

(2×4021)=(8021)=8021 (\frac{ 2\times40}{21})= (\frac{ 80}{21})=\frac{ 80}{21}

Reminder - How do we convert an improper fraction to a mixed number?

In order to determine the numerator - we need to check how many times the denominator goes into the numerator and add the remainder to the numerator.

For the denominator – we don't change anything.

In this exercise, the numerator is 80 and the denominator is 21

21 goes into 80 three times with a remainder of 17

8021=3 1721 \frac{ 80}{21}=3\text{ }\frac{17}{21}

Therefore the answer is option a -

3 1721 3\text{ }\frac{17}{21}

3

Final Answer

31721 3\frac{17}{21}

Practice Quiz

Test your knowledge with interactive questions

\( 100-(5+55)= \)

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Commutative, Distributive and Associative Properties questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations