Solve 2×(200÷(35×3)): Order of Operations Challenge

Let's recall the order of operations: calculating what's in parentheses, multiplication and division (from left to right), addition and subtraction (from left to right)

We emphasize that when there are parentheses within parentheses, we start with the innermost ones first.

$2\operatorname{\times}(200:(35\operatorname{\times}3))=$

In this exercise, there are only multiplication and division operations and parentheses within parentheses.

Therefore, we will first perform the operation in the inner parentheses, and after calculating we can remove the inner parentheses. We'll continue doing this until there are no more parentheses in the exercise.

$2\times(200:(35\times3))=2\times(200:(105))=$

$2\times(200:(105))= 2\times(200:105) =$

Let's represent the part of the exercise we got in the inner parentheses as a fraction and try to reduce the fraction

Reminder - How do we approach reducing a fraction? Divide both numerator and denominator by the same number

$2\times(200:105)=2\times(\frac{200}{105})=$
The largest number by which we can reduce the fraction is 5

$2\times(\frac{200}{105})= 2\times(\frac{200:5}{105:5})=$

$2\times(\frac{200:5}{105:5})= 2\times(\frac{40}{21})=$

$(\frac{ 2\times40}{21})= (\frac{ 80}{21})=\frac{ 80}{21}$

Reminder - How do we convert an improper fraction to a mixed number?

To find the numerator - we need to check how many times the denominator goes into the numerator and add the remainder to the numerator.

For the denominator – we don't change anything.

In this exercise, the numerator is 80 and the denominator is 21

21 goes into 80 three times with a remainder of 17

$\frac{ 80}{21}=3\text{ }\frac{17}{21}$

Therefore the answer is option a -

$3\text{ }\frac{17}{21}$