Solve Chain Division: -81:-27·6:-2 Step by Step

81:276:2= -81:-27\cdot6:-2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:07 Let's solve this problem together.
00:11 First, we can write each division as a fraction.
00:21 Remember, a negative divided by a negative is always positive.
00:32 And a negative divided by a positive is always negative.
00:43 Now, let’s break down eighty-one into factors: twenty-seven and three.
00:51 Next, let's break down six into factors: two and three.
00:59 Let's reduce the fractions as much as we can.
01:08 Positive times negative is always negative, so keep that in mind.
01:16 And that's how we find the solution to this question!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

81:276:2= -81:-27\cdot6:-2=

2

Step-by-step solution

Let's write the exercise as a multiplication of fractions:

(81:27)×(6:2)= (-81:-27)\times(6:-2)=

8127×62= \frac{-81}{-27}\times\frac{6}{-2}=

Note that in the first fraction we are dividing between two negative numbers, therefore the result must be a positive number.

Note that in the second fraction we are dividing between a positive number and a negative number, therefore the result must be a negative number.

Therefore:

8127×62= \frac{81}{27}\times-\frac{6}{2}=

Let's break down 81 into a multiplication exercise and 6 into a multiplication exercise:

27×327×2×32= \frac{27\times3}{27}\times-\frac{2\times3}{2}=

Let's reduce the 27 and the 2 in the numerator and denominator of the fraction and we get:

3×3= 3\times-3=

Note that we are multiplying between a positive number and a negative number, therefore the result must be a negative number:

9 -9

3

Final Answer

9 -9

Practice Quiz

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What will be the sign of the result of the next exercise?

\( (-2)\cdot(-4)= \)

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