Solve (7×5×2)^(y+4): Complete the Exponential Expression

Question

Insert the corresponding expression:

(7×5×2)y+4= \left(7\times5\times2\right)^{y+4}=

Video Solution

Solution Steps

00:00 Simplify the following problem
00:03 In order to open parentheses with a multiplication operation and an outside exponent
00:07 We'll raise each factor to the power
00:12 We'll apply this formula to our exercise
00:15 Note that our exponent is actually the sum and it's the entire power (N)
00:20 Therefore we'll raise each factor to this power
00:30 This is the solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the current expression and its structure.
  • Step 2: Apply the power of a product rule.
  • Step 3: Simplify the expression by distributing the exponent to each factor.

Now, let's work through each step:
Step 1: The given expression is (7×5×2)y+4(7 \times 5 \times 2)^{y+4}. This is a product inside the parentheses raised to a power.
Step 2: According to the power of a product rule, (a×b×c)n=an×bn×cn(a \times b \times c)^n = a^n \times b^n \times c^n. We can apply this rule here.
Step 3: Applying the rule, the expression becomes (7)y+4×(5)y+4×(2)y+4(7)^{y+4} \times (5)^{y+4} \times (2)^{y+4}.

Therefore, the correctly expanded expression is 7y+4×5y+4×2y+4 7^{y+4}\times5^{y+4}\times2^{y+4} .

Answer

7y+4×5y+4×2y+4 7^{y+4}\times5^{y+4}\times2^{y+4}