25−2+35= \frac{2}{5}-2+\frac{3}{5}= 52−2+53=
We can use the substitutive property to reorder and make solving the equation simpler:
25+35−2= \frac{2}{5}+\frac{3}{5}-2= 52+53−2=
We first add the fractions:
2+35=55=1 \frac{2+3}{5}=\frac{5}{5}=1 52+3=55=1
Now we obtain the exercise:
1−2=−1 1-2=-1 1−2=−1
−1 -1 −1