Solve (2×3)/(7×9) Raised to the 7th Power: Complete Solution

Question

Insert the corresponding expression:

(2×37×9)7= \left(\frac{2\times3}{7\times9}\right)^7=

Video Solution

Solution Steps

00:00 Simplify the following problem
00:03 According to the laws of exponents, a fraction raised to the power (N)
00:07 equals the numerator and denominator, each raised to the same power (N)
00:12 Note that both the numerator and denominator are products
00:16 We'll apply this formula to our exercise, making sure to use parentheses
00:23 According to the laws of exponents, a product raised to a power (N)
00:28 equals the product of each factor raised to that power (N)
00:32 We'll apply this formula to our exercise
00:39 This is the solution

Step-by-Step Solution

To solve this problem, we'll rewrite the expression using the rules of exponents.

  • Step 1: Identify the initial expression as (2×37×9)7\left(\frac{2 \times 3}{7 \times 9}\right)^7.
  • Step 2: Apply the rule (ab)n=anbn\left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} to distribute the exponent of 7 to both the numerator and denominator.
  • Step 3: Rewrite the expression as (2×3)7(7×9)7\frac{(2 \times 3)^7}{(7 \times 9)^7}.
  • Step 4: Apply the exponent rule (ab)n=an×bn(ab)^n = a^n \times b^n to both the numerator and the denominator.

Following these steps, we can express:

(2×3)7(7×9)7=27×3777×97\frac{(2 \times 3)^7}{(7 \times 9)^7} = \frac{2^7 \times 3^7}{7^7 \times 9^7}.

Therefore, the correct answer is 27×3777×97\frac{2^7 \times 3^7}{7^7 \times 9^7}, which corresponds to choice 3.

Answer

27×3777×97 \frac{2^7\times3^7}{7^7\times9^7}