00:00 Solve the following problem
00:03 A "regular" root is of the order 2
00:11 When we have a number (A) to the power of (B) in a root of order (C)
00:15 The result equals the number (A) to the power of their product (B times C)
00:19 We'll apply this formula to our exercise
00:25 When we have a root of the multiplication (A times B)
00:28 It can be written as multiplication of the root of each term
00:33 We'll apply this formula to our exercise, and proceed to break down the root
00:44 When we have a number (A) to the power of (B) in a root of order (C)
00:47 The result equals the number (A) to the power of their quotient (B divided by C)
00:52 We'll apply this formula to our exercise, and proceed to calculate the power quotient
01:05 We'll apply this formula again in the reverse direction, converting from power to root
01:18 This is the solution