71a+12b−(25ab+4a)=? 71a+12b-(25ab+4a)=\text{?} 71a+12b−(25ab+4a)=?
First, we tackle the parentheses.
Remember that when we multiply a positive number by a negative number, the result will be negative.
Now we get:
71a+12b−25ab−4a= 71a+12b-25ab-4a= 71a+12b−25ab−4a=
Now we add the coefficients a:
71a−4a=67a 71a-4a=67a 71a−4a=67a
67a+12b−25ab 67a+12b-25ab 67a+12b−25ab