35y−(10y+35z+12y)=? 35y-(10y+35z+12y)=\text{?} 35y−(10y+35z+12y)=?
First, we open the parentheses and change the sign accordingly.
Since there are only positive numbers inside the parentheses, multiplying by minus will give us negative numbers:
35y−10y−35z−12y= 35y-10y-35z-12y= 35y−10y−35z−12y=
Now we group the factors and:
35y−10y−12y=25y−12y=13y 35y-10y-12y=25y-12y=13y 35y−10y−12y=25y−12y=13y
Now we obtain:
13y−35z 13y-35z 13y−35z