22x+1⋅25⋅23x= 2^{2x+1}\cdot2^5\cdot2^{3x}= 22x+1⋅25⋅23x=
Since the bases are the same, the exponents can be added:
2x+1+5+3x=5x+6 2x+1+5+3x=5x+6 2x+1+5+3x=5x+6
25x+6 2^{5x+6} 25x+6