Simplify the Expression: 2^(2x+1) · 2^5 · 2^(3x)

22x+12523x= 2^{2x+1}\cdot2^5\cdot2^{3x}=

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's simplify this expression.
00:13 When multiplying powers with the same base, add their exponents together.
00:19 This rule works for any number of bases.
00:22 Now, we'll apply this rule to our problem.
00:27 Let's add up all the exponents.
00:35 Now, let's combine those factors.
00:46 And there we have it, this is the solution.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

22x+12523x= 2^{2x+1}\cdot2^5\cdot2^{3x}=

2

Step-by-step solution

We'll use the law of exponents for multiplying terms with identical bases:

aman=am+n a^m\cdot a^n=a^{m+n}
Note that this law applies to any number of terms being multiplied, not just two terms. For example, when multiplying three terms with the same base, we get:

amanak=am+nak=am+n+k a^m\cdot a^n\cdot a^k=a^{m+n}\cdot a^k=a^{m+n+k}
When we used the above law of exponents twice, we can also perform the same calculation for four terms in multiplication and so on...

Let's return to the problem:

Notice that all terms in the multiplication have the same base, so we'll use the above law:

22x+12523x=22x+1+5+3x=25x+6 2^{2x+1}\cdot2^5\cdot2^{3x}=2^{2x+1+5+3x}=2^{5x+6}

Therefore, the correct answer is a.

3

Final Answer

25x+6 2^{5x+6}

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Exponents Rules questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations