Simplify (ax)^21 / (xa)^6: Advanced Exponent Rules Practice

Insert the corresponding expression:

(a×x)21(x×a)6= \frac{\left(a\times x\right)^{21}}{\left(x\times a\right)^6}=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:03 The order of factors in multiplication doesn't matter
00:07 We'll use this formula in our exercise and switch between the factors
00:11 We'll use the formula for dividing exponents
00:13 Any number (A) to the power of (N) divided by the same base (A) to the power of (M)
00:16 equals the number (A) to the power of the difference of exponents (M-N)
00:20 We'll use this formula in our exercise
00:24 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Insert the corresponding expression:

(a×x)21(x×a)6= \frac{\left(a\times x\right)^{21}}{\left(x\times a\right)^6}=

2

Step-by-step solution

We start with the given expression:
(a×x)21(x×a)6 \frac{\left(a\times x\right)^{21}}{\left(x\times a\right)^6} .

Firstly, notice that the terms inside the parentheses in both the numerator and the denominator are the same: a×x a \times x and x×a x \times a , which are equivalent due to the commutative property of multiplication.

Thus, we can rewrite the expression in terms of (ax) (ax) as follows:
(ax)21(ax)6 \frac{\left(a x\right)^{21}}{\left(a x\right)^6} .

We will apply the power of a quotient rule for exponents, which states that:

  • aman=amn \frac{a^m}{a^n} = a^{m-n} , where a0 a \neq 0 .

Using this rule to simplify the expression, we have:

(ax)21(ax)6=(ax)216=(ax)15 \frac{(ax)^{21}}{(ax)^6} = (ax)^{21-6} = (ax)^{15} .

Thus, the expression simplifies to (a×x)15 (a \times x)^{15} .

Therefore, the solution to the question is:
(x×a)15 \left(x\times a\right)^{15} .

3

Final Answer

(x×a)15 \left(x\times a\right)^{15}

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\( 112^0=\text{?} \)

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