Reduce the Expression: 8^(3x) × 8^(3y) × 8^(2y+x)

Question

Reduce the following equation:

83x×83y×82y+x= 8^{3x}\times8^{3y}\times8^{2y+x}=

Video Solution

Solution Steps

00:00 Simplify the following problem
00:04 According to the laws of exponents, the multiplication of exponents with equal bases (A)
00:08 equals the same base raised to the sum of the exponents (N+M)
00:12 We will apply this formula to our exercise
00:16 We'll maintain the base and add the exponents together
00:36 Let's group the factors together
00:41 This is the solution

Step-by-Step Solution

To solve this problem, let's simplify the expression 83x×83y×82y+x 8^{3x} \times 8^{3y} \times 8^{2y+x} using exponent rules:

Step 1: Identify the exponents in each term:
- The first term is 83x8^{3x} with an exponent of 3x3x.
- The second term is 83y8^{3y} with an exponent of 3y3y.
- The third term is 82y+x8^{2y+x} with an exponent of 2y+x2y+x.

Step 2: Apply the multiplication of powers rule:
Since all terms have the same base of 8, add the exponents: (3x)+(3y)+(2y+x)(3x) + (3y) + (2y + x).

Step 3: Simplify the expression:
Adding the terms in the exponent gives us: 3x+3y+2y+x=4x+5y3x + 3y + 2y + x = 4x + 5y.

Therefore, the simplified expression is 84x+5y 8^{4x+5y} .

Answer

84x+5y 8^{4x+5y}