Find the Passing Points: y = 6(2x + 4) + x

Question

Through which points does the function below pass?

y=6(2x+4)+x y=6(2x+4)+x

Video Solution

Solution Steps

00:00 Find which points are on the line
00:03 Open parentheses properly, multiply by each factor
00:14 This is the line equation
00:17 In each point, the left number represents the X-axis and the right represents Y
00:21 We'll substitute each point in the line equation and see if it's possible
00:28 Not possible, therefore the point is not on the line
00:31 We'll use the same method for all points and find which ones are on the line
00:34 Let's move to this point
00:43 Not possible, therefore the point is not on the line
00:50 Let's move to this point
01:01 Not possible, therefore the point is not on the line
01:05 Let's move to this point
01:15 Possible, therefore the point is on the line
01:18 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Simplify the expression for y=6(2x+4)+x y = 6(2x+4) + x .
  • Step 2: Calculate y y at x=0 x = 0 .

First, let's simplify the expression for y y :

y=6(2x+4)+x y = 6(2x + 4) + x
=6×2x+6×4+x = 6 \times 2x + 6 \times 4 + x
=12x+24+x = 12x + 24 + x
=13x+24 = 13x + 24

Now, let's evaluate y y when x=0 x = 0 :

y=13(0)+24 y = 13(0) + 24
=0+24 = 0 + 24
=24 = 24

This means the function passes through the point (0,24) (0, 24) . Therefore, the solution to the problem is (0,24) (0, 24) .

Answer

(0,24) (0,24)