Solve the following exercise
(2x−3)(5x−7)=
To solve the exercise (2x−3)(5x−7), we must expand the expression by using the distributive property, commonly referred to as the FOIL method for binomials.
- First, multiply the first terms of each binomial: 2x⋅5x=10x2.
- Outside, multiply the outer terms of the binomials: 2x⋅−7=−14x.
- Inside, multiply the inner terms of the binomials: −3⋅5x=−15x.
- Last, multiply the last terms of the binomials: −3⋅−7=21.
After performing these operations, the expanded expression is:
10x2−14x−15x+21.
The next step is to combine the like terms. In this case, the like terms are the linear terms −14x and −15x:
10x2−14x−15x+21=10x2−29x+21.
Thus, after simplifying, the expression is 10x2−29x+21.
Therefore, the solution to the expression (2x−3)(5x−7) is 10x2−29x+21.
10x2−29x+21