Expand (1/3a + b)(9b + 12): Binomial Multiplication with Fractions

Question

(13a+b)(9b+12)= (\frac{1}{3}a+b)(9b+12)=

Video Solution

Step-by-Step Solution

The given expression is (13a+b)(9b+12)(\frac{1}{3}a + b)(9b + 12). We will expand this expression using the distributive property:

Step 1: Multiply the first terms of each binomial:

  • 13a×9b=3ab\frac{1}{3}a \times 9b = 3ab

Step 2: Multiply the outer terms:

  • 13a×12=4a\frac{1}{3}a \times 12 = 4a

Step 3: Multiply the inner terms:

  • b×9b=9b2b \times 9b = 9b^2

Step 4: Multiply the last terms:

  • b×12=12bb \times 12 = 12b

Combine all the resulting terms together:

9b2+3ab+4a+12b9b^2 + 3ab + 4a + 12b

Therefore, the solution to the problem is 9b2+3ab+4a+12b 9b^2 + 3ab + 4a + 12b .

Answer

9b2+3ab+4a+12b 9b^2+3ab+4a+12b