Evaluate 8(x-7)+4(6-2y) with Substitution: x=0, y=-1

Question

What will be the result of this algebraic expression:

8(x7)+4(62y) 8(x-7)+4(6-2y)

if we place

x=0,y=1 x=0,y=-1

Video Solution

Step-by-Step Solution

We have the given exercise, and it has two variables, X and Y.

In this case, we are given the values of these variables,

Therefore, what we need to do is substitute them in the relevant place in the exercise:

8(x-7)+4(6-2y)=

We know that x=0, so we will replace every X in the exercise with 0:

8(0-7)+4(6-2y)=
8(-7)+4(6-2y)=
-56+4(6-2y)=

We'll do the same thing with y, knowing that it equals -1

-56+4(6-2*(-1))=
-56+4(6-(-2)))=

-56+4(8)=

-56+32=

-24

And that's the solution!

Answer

24 -24