Evaluate -2m:(m+8):1/m with m=1 and m=-1: Sequential Division Challenge

Question

In front of you an algebraic expression:

2m:(m+8):1m -2m:(m+8):\frac{1}{m}

Replace and calculate once m=1 m=1 and once again m=1 m=-1

Video Solution

Step-by-Step Solution

Let's start with the first option.

Let's substitute the data in the expression:

2×(1):(1+8):11= -2\times(1):(1+8):\frac{1}{1}=

We'll solve the multiplication (a negative number multiplied by a positive number gives a negative result), then solve what's in parentheses, and finally the simple fraction:

2:9:1= -2:9:1=

We'll solve from left to right.

Let's write the division as a simple fraction:

29:1=29 -\frac{2}{9}:1=-\frac{2}{9}

Let's continue with the second option.

Let's substitute the data in the expression:

2×(1):(1+8):11= -2\times(-1):(-1+8):\frac{1}{-1}=

First, we'll solve the multiplication (we're multiplying two negative numbers so the result will be positive), then the parentheses, and finally the fraction (we're dividing a positive number by a negative number so the result will be negative):

2:7:1= 2:7:-1=

We'll solve from left to right, let's write the division as a simple fraction:

+27:(1)= +\frac{2}{7}:(-1)=

Since we're dividing a positive number by a negative number, the result must be negative:

27 -\frac{2}{7}

Therefore, the final answer is:

1=29,2=27 1=-\frac{2}{9},2=-\frac{2}{7}

Answer

27,29 -\frac{2}{7},-\frac{2}{9}