Determine the Largest Value Among Given Numbers

Question

Choose the largest value

Video Solution

Solution Steps

00:00 Choose the largest value
00:03 When multiplying the root of a number (A) by the root of another number (B)
00:06 The result equals the root of their product (A times B)
00:09 We'll use this formula in our exercise and calculate the products
00:12 We'll use this method for each expression and find the largest one
00:25 And this is the solution to the question

Step-by-Step Solution

To determine which of the suggested options has the largest numerical value, we will use three laws of exponents:

a. Definition of root as an exponent:

an=a1n \sqrt[n]{a}=a^{\frac{1}{n}} b. Law of exponents for an exponent applied to a product in parentheses (in reverse order):

anbn=(ab)n a^n\cdot b^n=(a\cdot b)^n c. Law of exponents for an exponent raised to an exponent:

(am)n=amn (a^m)^n=a^{m\cdot n} Let's deal with each of the suggested options (in the answers), starting by converting the square root to exponent notation, using the law of exponents mentioned in a' earlier:

55512512222122123331231244412412 \sqrt{5}\cdot\sqrt{5} \rightarrow 5^{\frac{1}{2}}\cdot5^{\frac{1}{2}}\\ \sqrt{2}\cdot\sqrt{2} \rightarrow 2^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\\ \sqrt{3}\cdot\sqrt{3} \rightarrow 3^{\frac{1}{2}}\cdot3^{\frac{1}{2}}\\ \sqrt{4}\cdot\sqrt{4} \rightarrow 4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}\\ Let's continue, since both terms in the product (in both options we are currently dealing with) have the same exponent, we can use the law of exponents mentioned in b' earlier and combine them in the parentheses product raised to the same exponent and then calculate the result of the product in parentheses:

512512(55)12=(52)12212212(22)12=(22)12312312(33)12=(32)12412412(44)12=(42)12 5^{\frac{1}{2}}\cdot5^{\frac{1}{2}} \rightarrow (5\cdot5)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}} \\ 2^{\frac{1}{2}}\cdot2^{\frac{1}{2}}\rightarrow(2\cdot2)^{\frac{1}{2}}=(2^2)^{\frac{1}{2}} \\ 3^{\frac{1}{2}}\cdot3^{\frac{1}{2}} \rightarrow (3\cdot3)^{\frac{1}{2}}=(3^2)^{\frac{1}{2}} \\ 4^{\frac{1}{2}}\cdot4^{\frac{1}{2}}\rightarrow(4\cdot4)^{\frac{1}{2}}=(4^2)^{\frac{1}{2}} \\ Let's continue, we'll apply the law of exponents mentioned in c' and calculate the exponent on the term (with exponent) in parentheses:

(52)125212=51=5(22)122212=21=2(42)124212=41=4(32)123212=31=3 (5^2)^{\frac{1}{2}}\rightarrow 5^{2\cdot \frac{1}{2}}=5^1=5 \\ (2^2)^{\frac{1}{2}}\rightarrow 2^{2\cdot \frac{1}{2}}=2^1=2 \\ (4^2)^{\frac{1}{2}}\rightarrow 4^{2\cdot \frac{1}{2}}=4^1=4 \\ (3^2)^{\frac{1}{2}}\rightarrow 3^{2\cdot \frac{1}{2}}=3^1=3 \\

We have therefore found that the number in option a' is the largest because:

5>4>3>2 Therefore, the correct answer is answer a'.

Answer

55 \sqrt{5}\cdot\sqrt{5}