Complete the Expression: (a⁵x⁵)/(7⁵b⁵) Algebraic Fraction

Question

Insert the corresponding expression:

a5×x575×b5= \frac{a^5\times x^5}{7^5\times b^5}=

Video Solution

Step-by-Step Solution

To solve this problem, our goal is to express the given quotient of powers in a simplified form using exponent laws.

  • Step 1: Understand the original expression. We have a5×x575×b5\frac{a^5 \times x^5}{7^5 \times b^5}.
  • Step 2: Recognize the structure. Notice that both the numerator and denominator are raised to the fifth power.
  • Step 3: Apply the property of exponents for quotients and products, which states that (mn)k=mknk\left(\frac{m}{n}\right)^k = \frac{m^k}{n^k} and (mn)k=mknk(m \cdot n)^k = m^k \cdot n^k.
  • Step 4: Rewrite the expression as a single fraction raised to the power of 5. Since each term in the numerator and denominator is raised to the fifth power separately, we combine them under a single power:
    • Numerator: a5×x5=(a×x)5a^5 \times x^5 = (a \times x)^5
    • Denominator: 75×b5=(7×b)57^5 \times b^5 = (7 \times b)^5
    • Therefore, a5×x575×b5=(a×x7×b)5\frac{a^5 \times x^5}{7^5 \times b^5} = \left(\frac{a \times x}{7 \times b}\right)^5.

Thus, the expression can be written as: (a×x7×b)5\left(\frac{a \times x}{7 \times b}\right)^5.

Now, comparing this with the answer choices provided:

  • Choice 1: (a×x)57×b5\frac{(a \times x)^5}{7 \times b^5} - does not match, as it retains the separate powers incorrectly.
  • Choice 2: (a×x7×b)5\left(\frac{a \times x}{7 \times b}\right)^5 - matches perfectly as derived.
  • Choice 3: a×x5(7×b)5\frac{a \times x^5}{(7 \times b)^5} - incorrect form compared to derived structure.
  • Choice 4: 7×(a×xb)57 \times \left(\frac{a \times x}{b}\right)^5 - unrelated format, doesn't match.

The correct choice is therefore Choice 2. This matches our derived expression using the laws of exponents correctly.

Answer

(a×x7×b)5 \left(\frac{a\times x}{7\times b}\right)^5