Complete the Expression: (a⁵x⁵)/(7⁵b⁵) Algebraic Fraction

Exponent Laws with Quotient-Product Form

Insert the corresponding expression:

a5×x575×b5= \frac{a^5\times x^5}{7^5\times b^5}=

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Step-by-step written solution

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1

Understand the problem

Insert the corresponding expression:

a5×x575×b5= \frac{a^5\times x^5}{7^5\times b^5}=

2

Step-by-step solution

To solve this problem, our goal is to express the given quotient of powers in a simplified form using exponent laws.

  • Step 1: Understand the original expression. We have a5×x575×b5\frac{a^5 \times x^5}{7^5 \times b^5}.
  • Step 2: Recognize the structure. Notice that both the numerator and denominator are raised to the fifth power.
  • Step 3: Apply the property of exponents for quotients and products, which states that (mn)k=mknk\left(\frac{m}{n}\right)^k = \frac{m^k}{n^k} and (mn)k=mknk(m \cdot n)^k = m^k \cdot n^k.
  • Step 4: Rewrite the expression as a single fraction raised to the power of 5. Since each term in the numerator and denominator is raised to the fifth power separately, we combine them under a single power:
    • Numerator: a5×x5=(a×x)5a^5 \times x^5 = (a \times x)^5
    • Denominator: 75×b5=(7×b)57^5 \times b^5 = (7 \times b)^5
    • Therefore, a5×x575×b5=(a×x7×b)5\frac{a^5 \times x^5}{7^5 \times b^5} = \left(\frac{a \times x}{7 \times b}\right)^5.

Thus, the expression can be written as: (a×x7×b)5\left(\frac{a \times x}{7 \times b}\right)^5.

Now, comparing this with the answer choices provided:

  • Choice 1: (a×x)57×b5\frac{(a \times x)^5}{7 \times b^5} - does not match, as it retains the separate powers incorrectly.
  • Choice 2: (a×x7×b)5\left(\frac{a \times x}{7 \times b}\right)^5 - matches perfectly as derived.
  • Choice 3: a×x5(7×b)5\frac{a \times x^5}{(7 \times b)^5} - incorrect form compared to derived structure.
  • Choice 4: 7×(a×xb)57 \times \left(\frac{a \times x}{b}\right)^5 - unrelated format, doesn't match.

The correct choice is therefore Choice 2. This matches our derived expression using the laws of exponents correctly.

3

Final Answer

(a×x7×b)5 \left(\frac{a\times x}{7\times b}\right)^5

Key Points to Remember

Essential concepts to master this topic
  • Quotient Rule: ambm=(ab)m \frac{a^m}{b^m} = \left(\frac{a}{b}\right)^m when exponents are equal
  • Product Rule: am×bm=(a×b)m a^m \times b^m = (a \times b)^m for same exponents
  • Check: Expand your final answer to match the original form ✓

Common Mistakes

Avoid these frequent errors
  • Combining exponents incorrectly with base terms
    Don't write (a×x)57×b5 \frac{(a \times x)^5}{7 \times b^5} = leaves denominator partially simplified! This mixes simplified and unsimplified forms incorrectly. Always apply exponent laws consistently to both numerator and denominator completely.

Practice Quiz

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\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can I combine the bases under one exponent?

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Because both the numerator and denominator have the same exponent (5)! The exponent law am×bm=(a×b)m a^m \times b^m = (a \times b)^m lets you factor out common exponents.

What if the exponents were different?

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If exponents are different, you cannot combine them this way! For example, a3×x572×b4 \frac{a^3 \times x^5}{7^2 \times b^4} stays as is because the exponents don't match.

How do I know which form is 'simplified'?

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The form (a×x7×b)5 \left(\frac{a \times x}{7 \times b}\right)^5 is simplified because it shows the single exponent applied to the entire fraction, making calculations easier.

Can I expand this back to check my answer?

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Yes! Expand (a×x7×b)5 \left(\frac{a \times x}{7 \times b}\right)^5 using (mn)k=mknk \left(\frac{m}{n}\right)^k = \frac{m^k}{n^k} to get (a×x)5(7×b)5=a5×x575×b5 \frac{(a \times x)^5}{(7 \times b)^5} = \frac{a^5 \times x^5}{7^5 \times b^5}

What's the difference between the answer choices?

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Choice 1 has 7×b5 7 \times b^5 (partially simplified), Choice 3 has a×x5 a \times x^5 (also partial). Only Choice 2 applies exponent laws completely and consistently to both parts.

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