Comparing Algebraic Expressions: Equivalence of (36t/r - 18rt²)

Question

Which of the expressions are equal to the expression?

36tr18rt2 \frac{36t}{r}-18rt^2

  1. 18(2trrt2) 18(\frac{2t}{r}-rt^2)

  2. 18r(2tr2t2) 18r(\frac{2t}{r^2}-t^2)

  3. 18(rt+2tr) -18(rt+\frac{2t}{r})

  4. 6t(6tr3rt) 6t(\frac{6t}{r}-3rt)

Video Solution

Step-by-Step Solution

To solve this problem, let's simplify and factor the given expression:

Original expression: 36tr18rt2 \frac{36t}{r} - 18rt^2

Step 1: Factor out the greatest common divisor, which is 18:

18(2trrt2) 18 \left( \frac{2t}{r} - rt^2 \right)

This matches the structure of choice 1.

Step 2: Substitute this back into the given options and simplify.

Option 1: 18(2trrt2) 18\left( \frac{2t}{r} - rt^2 \right)

This is identical to the factored form of the original.

Option 2: 18r(2tr2t2) 18r\left( \frac{2t}{r^2} - t^2 \right)

Expand and simplify:

=18r2tr218rt2 = 18r \cdot \frac{2t}{r^2} - 18r \cdot t^2

=36tr18rt2 = \frac{36t}{r} - 18rt^2

This matches the original expression.

Option 3: 18(rt+2tr) -18(rt + \frac{2t}{r})

Expand and simplify:

=18rt36tr = -18rt - \frac{36t}{r}

This does not match the original expression.

Option 4: 6t(6tr3rt) 6t\left( \frac{6t}{r} - 3rt \right)

Expand and simplify:

=6t6tr6t3rt = 6t \cdot \frac{6t}{r} - 6t \cdot 3rt

=36t2r18rt2 = \frac{36t^2}{r} - 18rt^2

This does not match the original expression.

Therefore, the correct options that are equivalent to the given expression are 1 and 2.

Answer

1,2 1,2