Insert the compatible sign:
>,<,=
(10×3)7□(15×2)−71
To solve this problem, we'll follow these steps:
- Step 1: Simplify both expressions using exponent rules.
- Step 2: Compare the simplified results to determine the appropriate sign.
First, simplify (10×3)7:
According to the power of a product rule, (ab)n=an×bn. So,
(10×3)7=107×37.
Now, simplify (15×2)−71:
Firstly, address the negative exponent: (ab)−n=an×bn1, so we have:
(15×2)−7=157×271.
Then, taking the reciprocal because of the double negative (when taking the reciprocal of inverse due to −n),
(15×2)−71=157×27.
Now, compare the expressions:
Since 10=2×5 and 15=3×5, consider breaking each base into prime factors:
107×37=(27×57)×37,
157×27=(37×57)×27.
Both 107×37 and 157×27 resolve to the same product since they are permutations of the same multiplication.
Thus, we conclude:
The two expressions are equal, so the compatible sign is =.
Therefore, the solution to the problem is =.