Compare (-2)⁷ and 2⁸: Exploring Negative Base Exponents

Question

Which is larger?

(2)728 (-2)^7⬜-2^8

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate (2)7 (-2)^7
  • Step 2: Calculate 28 -2^8
  • Step 3: Compare the two results

Now, let's work through each step:

Step 1: Calculate (2)7 (-2)^7 .

Using the power of negative numbers rule, (2)7 (-2)^7 is a negative number because 7 is odd. We perform the calculation:

(2)7=(2×2×2×2×2×2×2)=128(-2)^7 = - (2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2) = -128.

Step 2: Calculate 28 -2^8 .

Here, 28 2^8 is positive since 8 is an even number:

28=2562^8 = 256.

But, note the negative sign in front: 28=(28)=256-2^8 = -(2^8) = -256.

Step 3: Compare (2)7(-2)^7 and 28-2^8:

We have (2)7=128(-2)^7 = -128 and 28=256-2^8 = -256. The comparison shows:

128>256-128 > -256.

Therefore, the correct comparison is (2)7>28(-2)^7 > -2^8.

By following the steps and verifying calculations, we conclude that (2)7>28 (-2)^7 > -2^8 .

Answer

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