Calculate Square Perimeter from Area Expression: (3²-1²)+2³

Question

Given a square whose area is

(3212)+23 (3^2-1^2)+2^3

What is the perimeter of this square?

Video Solution

Solution Steps

00:00 Find the perimeter of the square
00:07 Calculate the area of the square
00:14 Calculate the powers
00:26 Solve the parentheses
00:31 This is the area of the square
00:37 Use the formula for calculating square area (side squared)
00:42 Extract the root to isolate side A
00:47 This is the length of the square's side
00:54 The perimeter of the square equals 4 times the side (because all sides are equal)
01:02 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we need to find the perimeter of a square given its area. The area of the square is given by the expression (3212)+23 (3^2-1^2)+2^3 .

Let us evaluate the expression to find the area:

  • Calculate 32 3^2 , which is 9 9 .
  • Calculate 12 1^2 , which is 1 1 .
  • Subtract to find 3212=91=8 3^2 - 1^2 = 9 - 1 = 8 .
  • Calculate 23 2^3 , which is 8 8 .
  • Add the results: 8+8=16 8 + 8 = 16 .

Therefore, the area of the square is 16 16 .

In general, the area of a square is given by the formula s2 s^2 , where s s is the side length of the square. To find the side length, we solve the equation:

  • s2=16 s^2 = 16 .
  • Taking the square root of both sides, we find s=16=4 s = \sqrt{16} = 4 .

The perimeter P P of a square with side length s s is given by the formula:

  • P=4s P = 4s .

Thus, substituting the value of s s :

  • P=4×4=16 P = 4 \times 4 = 16 .

Therefore, the perimeter of the square is 16 16 .

Answer

16 16