41×54=
\( \frac{1}{4}\times\frac{4}{5}= \)
\( \frac{4}{4}\times\frac{1}{2}= \)
\( \frac{3}{2}\times1\times\frac{1}{3}= \)
\( \frac{1}{4}\times\frac{1}{2}= \)
\( \frac{3}{4}\times\frac{1}{2}= \)
To multiply fractions, we multiply numerator by numerator and denominator by denominator
1*4 = 4
4*5 = 20
4/20
Note that we can simplify this fraction by 4
4/20 = 1/5
When we have a multiplication of fractions, we multiply numerator by numerator and denominator by denominator:
4*1 = 4
4*2 8
We can reduce the result, so we get:
4:4 = 1
8:4 2
And thus we arrived at the result, one half.
Similarly, we can see that the first fraction (4/4) is actually 1, because when the numerator and denominator are equal it means the fraction equals 1,
and since we know that any number multiplied by 1 remains the same number, we can conclude that the solution remains one half.
According to the order of operations rules, we will solve the exercise from left to right since there are only multiplication operations:
We will multiply the three by three and get:
1\over2
\( \frac{1}{6}\times\frac{1}{3}= \)
\( \frac{1}{4}\times\frac{3}{2}= \)
\( \frac{2}{3}\times\frac{5}{7}= \)
\( \frac{3}{5}\times\frac{1}{2}= \)
\( \frac{3}{4}\times\frac{1}{2}= \)
\( \frac{1}{6}\times\frac{2}{3}= \)
\( \frac{1}{3}\times\frac{4}{7}= \)
\( \frac{2}{5}\times\frac{1}{2}= \)
\( \frac{2}{4}\times\frac{4}{5}= \)
\( \frac{2}{3}\times\frac{1}{4}= \)
\( \frac{2}{4}\times\frac{1}{2}= \)
\( \frac{2}{3}\times\frac{3}{4}= \)
\( \frac{6}{8}\times\frac{5}{6}= \)
\( \frac{2}{7}\times\frac{3}{5}= \)
\( \frac{7}{8}\times\frac{4}{6}= \)