41×54=
\( \frac{1}{4}\times\frac{4}{5}= \)
\( \frac{4}{4}\times\frac{1}{2}= \)
Solve the following exercise:
\( \frac{3}{2}\times1\times\frac{1}{3}=\text{ ?} \)
\( \frac{1}{4}\times\frac{1}{2}= \)
\( \frac{3}{4}\times\frac{1}{2}= \)
To multiply fractions, we multiply numerator by numerator and denominator by denominator
1*4 = 4
4*5 = 20
4/20
Note that we can simplify this fraction by 4
4/20 = 1/5
When we have a multiplication of fractions, we multiply numerator by numerator and denominator by denominator:
4*1 = 4
4*2 8
We can reduce the result, so we get:
4:4 = 1
8:4 2
And thus we arrived at the result, one half.
Similarly, we can see that the first fraction (4/4) is actually 1, because when the numerator and denominator are equal it means the fraction equals 1,
and since we know that any number multiplied by 1 remains the same number, we can conclude that the solution remains one half.
Solve the following exercise:
According to the order of operations, we must solve the exercise from left to right since it contains only multiplication operations:
Then, we will multiply the 3 by 3 to get:
\( \frac{1}{6}\times\frac{1}{3}= \)
\( \frac{1}{4}\times\frac{3}{2}= \)
\( \frac{2}{3}\times\frac{5}{7}= \)
\( \frac{3}{5}\times\frac{1}{2}= \)
\( \frac{3}{4}\times\frac{1}{2}= \)
\( \frac{1}{3}\times\frac{4}{7}= \)
\( \frac{2}{5}\times\frac{1}{2}= \)
\( \frac{2}{4}\times\frac{4}{5}= \)
\( \frac{2}{3}\times\frac{1}{4}= \)
\( \frac{2}{4}\times\frac{1}{2}= \)
\( \frac{2}{3}\times\frac{3}{4}= \)
\( \frac{6}{8}\times\frac{5}{6}= \)
\( \frac{1}{6}\times\frac{2}{3}= \)
\( \frac{2}{7}\times\frac{3}{5}= \)
\( \frac{7}{8}\times\frac{4}{6}= \)