41×(31+21)=
\( \frac{1}{4}\times(\frac{1}{3}+\frac{1}{2})= \)
\( \frac{1}{4}\times\frac{1}{2}+\frac{3}{8}= \)
\( \frac{1}{4}\times\frac{4}{5}+\frac{11}{20}= \)
\( \frac{3}{4}\times\frac{3}{4}-\frac{1}{4}= \)
\( \frac{1}{2}\times\frac{1}{2}+\frac{3}{4}= \)
According to the order of operations, we will first solve the expression in parentheses.
Note that since the denominators are not common, we will look for a number that is both divisible by 2 and 3. That is 6.
We will multiply one-third by 2 and one-half by 3, now we will get the expression:
Let's solve the numerator of the fraction:
We will combine the fractions into a multiplication expression:
\( \frac{4}{5}\times\frac{1}{2}+\frac{3}{10}= \)
\( \frac{3}{5}\times\frac{2}{3}+\frac{2}{5}= \)
\( \frac{2}{3}\times\frac{1}{3}+\frac{2}{9}= \)
\( \frac{3}{4}\times\frac{1}{2}+\frac{5}{8}= \)
\( \frac{4}{4}\times\frac{1}{2}+\frac{3}{8}= \)
\( \frac{2}{3}\times\frac{2}{3}+\frac{4}{9}= \)
Solve the following:
\( \frac{3}{5}\times\frac{1}{2}+\frac{3}{10}= \)
Solve the following: