Multiplication and division: Solving the problem

According to the rules of the order of operations, the exercise which contains both multiplication and division should be solved from left to right.

$30:5=6$

$6\times2=12$

According to the rules of the order of operations we should first solve the exercise from left to right since it only contains a division operation:

$80:4=20$

$20:2=10$

$10:5=2$

To solve the equation, follow the order of operations (PEMDAS/BODMAS):

1. Perform the multiplication and division from left to right:

$6 \times 3 = 18$

$18 \div 2 = 9$

2. Subtract the result from 50:

$50 - 9 = 41$

Therefore, the correct answer is 41.

To solve the equation, follow the order of operations (PEMDAS/BODMAS):

1. Perform the division:

$10 \div 5 = 2$

2. Perform the multiplication:

$2 \times 2 = 4$

3. Substitute back into the equation and perform the addition and subtraction from left to right:

$15 + 4 - 3 = 16$

Therefore, the correct answer is $16$

According to the order of operations, we will first solve the multiplication exercises.

We will put them in parentheses so that we don't get confused later in the solution:

$25-(3\times4)+(4\times2)=$

Let's solve the multiplication exercises:

$3\times4=12$

$4\times2=8$

We get:

$25-12+8=$

Let's solve the exercise from left to right:

$25-12=13$

$13+8=21$

According to the order of operations rules, we first enter the multiplication and division exercises into parentheses:

$(5\times5\times2)-(12:4)=$

Now let's solve the exercises in parentheses from left to right:

$5\times5=25$

$25\times2=50$

$12:4=3$

We obtain the following exercise:

$50-3=47$

According to the order of operations rules, we first insert the multiplication and division exercises into parentheses:

$(24:2)-4-(3:3)=$

Let's solve the exercises in parentheses:

$24:2=12$

$3:3=1$

Now we have the expression:

$12-4-1=$

Let's solve the expression from left to right:

$12-4=8$

$8-1=7$

According to the rules of the order of operations, we solve the exercise from left to right since the exercise only involves multiplication and division:

$80:10=8$

$8:5=\frac{8}{5}$

$\frac{8}{5}\times5=8$

$8:25=\frac{8}{25}$

According to the rules for the order of operations, we will place multiplication and division exercises in parentheses:

$(24:8:3)+(2\cdot6\cdot2)+19=$

We solve the division exercises in parentheses from left to right:

$24:8=3$

$3:3=1$

We solve the multiplication exercises in parentheses from left to right:

$2\times6=12$

$12\times2=24$

Now we get the exercise:

$1+24+19=$

We solve the exercise from left to right:

$1+24=25$

$25+19=44$

According to the rules for the order of operations, we will isolate the multiplication and division exercises in parentheses:

$(14:2\cdot5:7)+12+25=$

We solve the exercise in parentheses from left to right:

$14:2=7$

$7\times5=35$

$35:7=5$

Now we obtain the exercise:

$5+12+25=$

We solve the exercise from left to right:

$5+12=17$

$17+25=42$

According to the order of operations rules, we'll place the division exercises in parentheses:

$(81:9:3)+18+27-10=$

Let's solve the expression in parentheses from left to right:

$81:9=9$

$9:3=3$

We should obtain the following expression:

$3+18+27-10=$

Let's solve the expression from left to right:

$3+18=21$

$21+27=48$

$48-10=38$

According to the rules for the order of operations, we will isolate the multiplication operations in parentheses:

$(9\cdot5\cdot5)+7-5+82-2=$

We solve the exercise in parentheses from left to right:

$9\times5=45$

$45\times5=225$

Now, we obtain the exercise:

$225+7-5+82-2=$

We solve the exercise from left to right

$225+7=232$

$232-5=227$

$227+82=309$

$309-2=307$

According to the order of operations rules, we first enter the multiplication and division operations into parentheses:

$(100:2)-(10:2)+(3\times4)-6-(5\times2)=$

Now let's solve the operations within the parentheses:

$100:2=50$

$10:2=5$

$3\times4=12$

$5\times2=10$

We obtain the following expression:

$50-5+12-6-10=$

Let's solve the expression from left to right:

$50-5=45$

$45+12=57$

$57-6=51$

$51-10=41$