What is the positive domain of the function below?
What is the positive domain of the function below?
\( y=(x-2)^2 \)
Find the negative area of the function
\( y+1=(x+3)^2 \)
Find the positive area of the function
\( y=(x+6)^2 \)
Find the positive area of the function
\( y=(x+5)^2 \)
Find the negative area of the function
\( y=(x+2)^2 \)
What is the positive domain of the function below?
In the first step, we place 0 in place of Y:
0 = (x-2)²
We perform a square root:
0=x-2
x=2
And thus we reveal the point
(2, 0)
This is the vertex of the parabola.
Then we decompose the equation into standard form:
y=(x-2)²
y=x²-4x+2
Since the coefficient of x² is positive, we learn that the parabola is a minimum parabola (smiling).
If we plot the parabola, it seems that it is actually positive except for its vertex.
Therefore the domain of positivity is all X, except X≠2.
all x,
Find the negative area of the function
-4 < x < -2
Find the positive area of the function
Find the positive area of the function
For each X
Find the negative area of the function
There is no
Find the negative area of the function
\( y-4=-(x-4)^2 \)
Find the negative area of the function
\( y+4=(x+6)^2 \)
Find the positive area of the function
\( y=-(x-3)^2 \)
Find the negative area of the function
\( y=-(x+4)^2 \)
Find the negative area of the function
x < 2 o x > 6
Find the negative area of the function
-8 < x < -4
Find the positive area of the function
There is no positive area.
Find the negative area of the function
For each X