Parabola of the Form y=(x-p)²: Identify the positive and negative domain

What is the positive domain of the function below?

$y=(x-2)^2$

In the first step, we place 0 in place of Y:

0 = (x-2)²

We perform a square root:

0=x-2

x=2

And thus we reveal the point

(2, 0)

This is the vertex of the parabola.

Then we decompose the equation into standard form:

y=(x-2)²

y=x²-4x+2

Since the coefficient of x² is positive, we learn that the parabola is a minimum parabola (smiling).

If we plot the parabola, it seems that it is actually positive except for its vertex.

Therefore the domain of positivity is all X, except X≠2.

all x, $x\ne2$

Find the positive area of the function

$y=(x+6)^2$

$x\ne-6$

Find the negative area of the function

$y=(x+2)^2$

There is no

Find the positive area of the function
$y=(x+5)^2$

For each X $x\ne5$

Find the negative area of the function

$y+1=(x+3)^2$

-4 < x < -2

Find the negative area of the function

$y=-(x+4)^2$

For each X $x\ne-4$

Find the negative area of the function

$y+4=(x+6)^2$

-8 < x < -4

Find the negative area of the function

$y-4=-(x-4)^2$

x < 2 o x > 6

Find the positive area of the function

$y=-(x-3)^2$

There is no positive area.