32−61−126=
\( \frac{2}{3}-\frac{1}{6}-\frac{6}{12}= \)
\( \frac{8}{10}-\frac{1}{5}-\frac{2}{10}= \)
\( \frac{5}{6}-\frac{2}{4}-\frac{1}{12}= \)
\( \frac{4}{10}-\frac{1}{5}-\frac{1}{10}= \)
\( \frac{8}{5}-\frac{2}{15}-\frac{2}{3}= \)
Let's try to find the lowest common multiple of 3, 6 and 12
To find the lowest common multiple, we find a number that is divisible by 3, 6 and 12
In this case, the common multiple is 12
Now let's multiply each number in the appropriate multiple to reach the multiple of 12
We will multiply the first number by 4
We will multiply the second number by 2
We will multiply the third number by 1
Now let's subtract:
We will divide the numerator and the denominator by 0 and get:
\( \frac{7}{5}-\frac{2}{15}-\frac{2}{3}= \)
\( \frac{4}{5}-\frac{2}{10}-\frac{1}{5}= \)
\( \frac{2}{3}-\frac{1}{6}-\frac{3}{12}= \)
\( \frac{4}{2}-\frac{6}{8}-\frac{1}{4}= \)
\( \frac{5}{6}-\frac{2}{4}-\frac{3}{12}= \)
\( \frac{10}{12}-\frac{2}{3}-\frac{1}{6}= \)
\( \frac{2}{3}+\frac{2}{15}-\frac{4}{5}= \)
\( \frac{1}{2}-\frac{3}{8}+\frac{2}{4}= \)
\( \frac{3}{6}-\frac{1}{3}-\frac{1}{12}= \)
\( \frac{3}{5}-\frac{1}{10}-\frac{1}{5}= \)
\( \frac{3}{2}-\frac{5}{8}-\frac{1}{4}= \)
\( \frac{4}{6}-\frac{1}{3}-\frac{1}{12}= \)
\( \frac{1}{3}+\frac{7}{15}-\frac{2}{5}= \)
\( \frac{10}{12}-\frac{1}{3}-\frac{2}{6}= \)